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如何根据列表的长度拆分字符向量

发布时间:2020-12-15 04:27:39 所属栏目:Java 来源:网络整理
导读:我有这样的角色矢量: a-c("tanaman","cabai","banget","hama","sakit","tanaman","koramil","nogosari","melaks","ecek","padi","ppl","ds","rambun") 我想根据列表的长度将字符向量拆分为列表,如下所示: split.char-list(c("tanaman","cabai"),c("banget"
我有这样的角色矢量:

a<-c("tanaman","cabai","banget","hama","sakit","tanaman","koramil","nogosari","melaks","ecek","padi","ppl","ds","rambun")

我想根据列表的长度将字符向量拆分为列表,如下所示:

split.char<-list(c("tanaman","cabai"),c("banget","penyakit","tanaman"),c("koramil","pengecekan","rambun"))

我正在尝试使用sapply(split.char,length)来定义列表split.char的长度

Length <- sapply(split.char,length)
for(i in Length){
  split(a,Length(i))
 }

但我没有得到所需的输出,我不断收到此警告消息:

1: In split.default(ok,Length) : data length is not a multiple of split variable
2: In split.default(ok,Length) : data length is not a multiple of split variable
3: In split.default(ok,Length) : data length is not a multiple of split variable

解决方法

您可以尝试以下方法:

split(x=a,f=rep(seq_along(Length),Length))

f必须与x具有相同的长度(如果它的长度为1或x的分隔符将被再循环).

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