java – 如何设置始终显示的警报?
发布时间:2020-12-15 04:22:39 所属栏目:Java 来源:网络整理
导读:现在,我只想在用户访问应用程序时获得某种电池状态指示.例如,如果设备已插入,则设备应该说充电和它的电平.如果设备已拔下,则不应显示任何内容.如果设备未充电且电池电量不足,则应显示电池电量不足指示. 我设置了大部分代码,但问题是,例如,如果我运行应用程序
现在,我只想在用户访问应用程序时获得某种电池状态指示.例如,如果设备已插入,则设备应该说充电和它的电平.如果设备已拔下,则不应显示任何内容.如果设备未充电且电池电量不足,则应显示电池电量不足指示.
我设置了大部分代码,但问题是,例如,如果我运行应用程序并且设备已插入,屏幕上会显示充电指示.如果我拔下设备,则不再显示充电但如果我重新插入设备,则仍然无法再显示充电.当设备插入或拔出,??电池电量不足或电量不足时,应始终显示电池警报.应始终显示信息更改. 所以这是我的广播接收器: private BroadcastReceiver mBatInfoReceiver = new BroadcastReceiver() { @Override public void onReceive(Context arg0,Intent intent) { //Battery level int level = intent.getIntExtra("level",0); //Plugged in Status int plugged = intent.getIntExtra(BatteryManager.EXTRA_PLUGGED,-1); //Battery Status int status = intent.getIntExtra(BatteryManager.EXTRA_STATUS,-1); //If the device is charging or contains a full status,it's charging boolean isCharging = status == BatteryManager.BATTERY_STATUS_CHARGING || status == BatteryManager.BATTERY_STATUS_FULL; //If the device isCharging and plugged in,then show that the battery is charging TextView batteryTextView = ((TextView) findViewById(R.id.charging)); TextView batteryLowTextView = ((TextView) findViewById(R.id.low_battery)); ImageView batteryLowImageView= ((ImageView) findViewById(R.id.low_battery_icon)); ImageView batteryImageView =((ImageView) findViewById(R.id.charging_battery_icon)); if (isCharging && plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB) { //Gets the 'last synced' string and sets to datetime of the last sync Resources resources = context.getResources(); String chargingString = String.format(resources.getString(R.string.charging),level); //Dynamically sets the value of the battery level batteryLowTextView.setVisibility(TextView.INVISIBLE); batteryLowImageView.setVisibility(ImageView.INVISIBLE); batteryTextView.setText(chargingString + "%"); } else if (level < LOW_BATTERY_LEVEL && !isCharging) { Resources resources = context.getResources(); String lowBatteryString = String.format(resources.getString(R.string.low_battery)); batteryTextView.setVisibility(TextView.INVISIBLE); batteryImageView.setVisibility(ImageView.INVISIBLE); batteryLowTextView.setText(lowBatteryString); } else if (!isCharging && level > LOW_BATTERY_LEVEL) { //do nothing batteryTextView.setVisibility(TextView.GONE); batteryImageView.setVisibility(ImageView.GONE); } } }; 在我的OnCreate方法中,我打电话 //calls registerReceiver to receive the broadcast for the state of battery this.registerReceiver(this.mBatInfoReceiver,new IntentFilter(Intent.ACTION_BATTERY_CHANGED)); 所以,我想知道我做错了什么?是bools吗? 解决方法
>你的if-then-else逻辑有很多漏洞(并且有@Vikram提到的问题).这可能导致接收器最终无所事事.尝试简化逻辑以删除所有漏洞.
>更新文本视图时,还必须记住首先使其(及其图像视图)可见. 这是if-then-else逻辑的替代品: if (isCharging) { //Gets the 'last synced' string and sets to datetime of the last sync Resources resources = context.getResources(); String chargingString = String.format(resources.getString(R.string.charging),level); //Dynamically sets the value of the battery level batteryLowTextView.setVisibility(TextView.INVISIBLE); batteryLowImageView.setVisibility(ImageView.INVISIBLE); batteryTextView.setText(chargingString + "%"); batteryTextView.setVisibility(TextView.VISIBLE); batteryImageView.setVisibility(ImageView.VISIBLE); } else if (level <= LOW_BATTERY_LEVEL) { Resources resources = context.getResources(); String lowBatteryString = String.format(resources.getString(R.string.low_battery)); batteryTextView.setVisibility(TextView.INVISIBLE); batteryImageView.setVisibility(ImageView.INVISIBLE); batteryLowTextView.setText(lowBatteryString); batteryLowTextView.setVisibility(TextView.VISIBLE); batteryLowImageView.setVisibility(ImageView.VISIBLE); } else { //show nothing batteryTextView.setVisibility(TextView.GONE); batteryImageView.setVisibility(ImageView.GONE); batteryLowTextView.setVisibility(TextView.GONE); batteryLowImageView.setVisibility(ImageView.GONE); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |