在Java中压缩时如何维护文件夹结构？
发布时间：2020-12-15 02:35:09 所属栏目：Java 来源：网络整理
导读：我想压缩一个像这样结构的文件夹： 温度/文件夹1 / file1的 温度/文件夹2 / file2的 温度/文件3 并完全保持目录结构. 目前,当我拉链时,我得到一个不保持目录结构的zip.看起来像这样 文件1 文件2 文件3 如何将文件添加到各自的文件夹中,就像所有普通的压缩应
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我想压缩一个像这样结构的文件夹：
温度/文件夹1 / file1的 温度/文件夹2 / file2的 温度/文件3 并完全保持目录结构. 如何将文件添加到各自的文件夹中,就像所有普通的压缩应用程序一样？ 这是我到目前为止的代码： package com.damastah.deflash;
import android.util.Log;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.ArrayList;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Compress {
private static final int BUFFER = 2048;
private ArrayList<File> _files;
private String _zipFile;
public Compress(ArrayList<File> files,String zipFile) {
_files = files;
_zipFile = zipFile;
}
public void zip() {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new FileOutputStream(_zipFile);
ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(
dest));
byte data[] = new byte[BUFFER];
Log.e("Compress - zip","test");
for (int i = 0; i < _files.size(); i++) {
Log.v("Compress","Adding: " + _files.get(i).getAbsolutePath());
FileInputStream fi = new FileInputStream(_files.get(i)
.getAbsolutePath());
origin = new BufferedInputStream(fi,BUFFER);
ZipEntry entry;
if (_files.get(i).getAbsolutePath().contains("."))
entry = new ZipEntry(_files
.get(i)
.getAbsolutePath()
.substring(
_files.get(i).getAbsolutePath()
.lastIndexOf("/") + 1));
else
entry = new ZipEntry(_files.get(i).getAbsolutePath());
out.putNextEntry(entry);
int count;
while ((count = origin.read(data,BUFFER)) != -1) {
out.write(data,count);
}
origin.close();
}
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
}
解决方法
我不是android开发人员所以请将此代码视为仅提示
class ZipCompress {
public static void main(String[] args) throws IOException {
String dir = "d:My folder";
// this entries I want to put in archives in the way they are now
String[] entries = { "tempfolder1file1.txt","tempfolder2file2.txt","tempfile3.txt" };
ZipOutputStream zipos = new ZipOutputStream(new BufferedOutputStream(
new FileOutputStream(dir + "archive.zip")));
// time to create entries and fill them with data
for (String entrie : entries) {
System.out.println("Writing file: " + dir + entrie);
// prepering file stream
BufferedInputStream fileStream = new BufferedInputStream(
new FileInputStream(dir + entrie));
//--------------------------------------------------------------------------
// Here we decide how we entry will look like in archive.
// We use only part of path from String[] entries
// like "tempfolder1file1.txt"
//--------------------------------------------------------------------------
ZipEntry newEntry = new ZipEntry(entrie);
newEntry.setComment("comment to entry: " + newEntry);
// now lets put this entry in archive
zipos.putNextEntry(newEntry);
// lets put data from file to current archive entry
int c;
while ((c = fileStream.read()) != -1)
zipos.write(c);
fileStream.close();
}
zipos.close();
}
}
编辑 我不知道你想在这做什么 if (_files.get(i).getAbsolutePath().contains("."))
entry = new ZipEntry(_files
.get(i)
.getAbsolutePath()
.substring(
_files.get(i).getAbsolutePath()
.lastIndexOf("/") + 1));
从我看到它删除文件的路径只留下文件名(类似于_files.get(i).getName()).如果这是真的那么这就是你的zip文件中没有文件夹结构的原因.你说zip条目应该只是那个文件名,没有任何文件夹. 因此,如果您希望zip文件包含路径的某些部分 String dir = "/my/full/path/to/folder/";
for (int i = 0; i < _files.size(); i++) {
...
if (_files.get(i).getAbsolutePath().contains(".")) {
entry = new ZipEntry(_files
.get(i).getAbsolutePath().replace(dir,""));
...
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