java – LocalDate减去Period得到错误的结果
发布时间：2020-12-14 16:23:49 所属栏目：Java 来源：网络整理
导读：LocalDate减去一个Period(如“28年,1个月和27天”),得到错误的结果. 但减去一个时期(只有天数单位,如“10282”天)得到正确的结果. 有什么需要注意的吗？ public static void main(String[] args) { printAgeAndBirthday(1989,2,22); printBirthdayFromPeriod
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LocalDate减去一个Period(如“28年,1个月和27天”),得到错误的结果.
但减去一个时期(只有天数单位,如“10282”天)得到正确的结果. public static void main(String[] args) {
printAgeAndBirthday(1989,2,22);
printBirthdayFromPeriod(28,1,27);
}
private static void printBirthdayFromPeriod(int years,int months,int days) {
final Period period = Period.of(years,months,days);
final LocalDate now = LocalDate.now();
final LocalDate birthday = now.minus(28,ChronoUnit.YEARS)
.minus(1,ChronoUnit.MONTHS)
.minus(27,ChronoUnit.DAYS);
System.out.println("your birthday is : "+ birthday);//1989-02-19
System.out.println("your birthday is : "+ now.minusYears(28).minusMonths(1).minusDays(27));//1989-02-19
System.out.println("your birthday is : "+ now.minus(period));//1989-02-19
System.out.println("your birthday is : "+period.subtractFrom(now));//1989-02-19
System.out.println("your birthday is : "+ now.minus(Period.ofDays(10282)));//1989-02-22
}
private static void printAgeAndBirthday(int year,int month,int dayOfMonth) {
LocalDate today = LocalDate.now();
LocalDate birthday = LocalDate.of(year,month,dayOfMonth);
Period p = Period.between(birthday,today);
long p2 = ChronoUnit.DAYS.between(birthday,today);
System.out.printf("You are %d years,%d months,and %d days old. (%d days total)%n",p.getYears(),p.getMonths(),p.getDays(),p2);
LocalDate nextBDay = birthday.withYear(today.getYear());
//If your birthday has occurred this year already,add 1 to the year.
if (nextBDay.isBefore(today) || nextBDay.isEqual(today)) {
nextBDay = nextBDay.plusYears(1);
}
Period p_1 = Period.between(today,nextBDay);
long p_2 = ChronoUnit.DAYS.between(today,nextBDay);
System.out.printf("There are %d months,and %d days until your next birthday. (%d total)%n",p_1.getMonths(),p_1.getDays(),p_2);
}
控制台日志： You are 28 years,1 months,and 27 days old. (10282 days total) There are 10 months,and 4 days until your next birthday. (310 total) your birthday is : 1989-02-19 your birthday is : 1989-02-19 your birthday is : 1989-02-19 your birthday is : 1989-02-19 your birthday is : 1989-02-22 java版本：jdk1.8.0_45 解决方法
您的案例可以简化为
LocalDate date1 = LocalDate.of(2017,22),date2 = LocalDate.of(2017,4,18);
Period p = Period.between(date1,date2);
System.out.println("date1 + p: "+date1.plus(p));
System.out.println("date2 - p: "+date2.minus(p));
这将打印 date1 + p: 2017-04-18 date2 - p: 2017-02-19 换句话说,年数是无关紧要的(除非其中一年是闰年而另一年不是,但在这里,两者都不是).以下说明了问题： February March April 19 20 21 22 23 24 25 26 27 28 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 ↑ │ ↑ ↑ │ └──────────────────────────── plus one Month ───────────────────────────────────────┴───────────────────────── plus 27 days ─────────────────────────────────────────┤ │ ↑ ↓ └───────────────────────── minus 27 days ────────────────────────────────────────┴─────────────────── minus one month ────────────────────────────────────────────────────────┘ 如果你改变方向,这将改变： Period p2 = Period.between(date2,date1);
System.out.println("date1 - p2: "+date1.minus(p2));
System.out.println("date2 + p2: "+date2.plus(p2));
这将打印 date1 - p2: 2017-04-15 date2 + p2: 2017-02-22 因此,当您以年,月和日表示期间时,方向变得相关.相反,两个日期之间的平均天数是不变的： LocalDate date1 = LocalDate.of(2017,18);
Period p = Period.ofDays((int)ChronoUnit.DAYS.between(date1,date2));
System.out.println("date1 + p: "+date1.plus(p));
System.out.println("date2 - p: "+date2.minus(p));
date1 + p: 2017-04-18 date2 - p: 2017-02-22 （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |