java – 调用Thread.isInterrupted()的性能成本是多少?
发布时间:2020-12-15 00:41:19 所属栏目:Java 来源:网络整理
导读:从 java源代码来看,它看起来像是本机代码.成本大致相当于易失性读取还是需要获取某种类型的锁定? 解决方法 Thread.isInterrupted()是一个非常便宜的函数.有一些更多的间接,但所有电话都足够快.总结一下: It must be possible for Java to emulate Thread.c
从
java源代码来看,它看起来像是本机代码.成本大致相当于易失性读取还是需要获取某种类型的锁定?
解决方法
Thread.isInterrupted()是一个非常便宜的函数.有一些更多的间接,但所有电话都足够快.总结一下:
Source: bool os::is_interrupted(Thread* thread,bool clear_interrupted) { assert(Thread::current() == thread || Threads_lock->owned_by_self(),"possibility of dangling Thread pointer"); OSThread* osthread = thread->osthread(); bool interrupted = osthread->interrupted(); if (interrupted && clear_interrupted) { osthread->set_interrupted(false); // consider thread->_SleepEvent->reset() ... optional optimization } return interrupted; }
volatile jint _interrupted; // Thread.isInterrupted state // Note: _interrupted must be jint,so that Java intrinsics can access it. // The value stored there must be either 0 or 1. It must be possible // for Java to emulate Thread.currentThread().isInterrupted() by performing // the double indirection Thread::current()->_osthread->_interrupted. .... volatile bool interrupted() const { return _interrupted != 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |