一道笔试题
发布时间：2020-12-14 06:30:02 所属栏目：Java 来源：网络整理
导读：今天去面试了一家外资公司，遇到一道笔试题 题目大概内容如下： 下面是我整理出来的代码： String email = "hongtenfoxmail.com.cn" isEmail = String result = isEmail ? "正确" : "不正确" System.out.println("邮箱 [" + email + "]格式是否正确：" + ind
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今天去面试了一家外资公司，遇到一道笔试题 题目大概内容如下： 下面是我整理出来的代码：
String email = "hongtenfoxmail.com.cn" isEmail = String result = isEmail ? "正确" : "不正确" System.out.println("邮箱 [" + email + "]格式是否正确：" +
indexFlag = lastFlag = String[] strs = email.split("@" if (strs.length > 0 && strs.length <= 2) {，谢谢
(email.lastIndexOf("@") != -1 && strs.length <= 2 String index = strs[0 String last = strs[1 indexFlag = String[] lastArray = last.split("." ( j = 0; j < lastArray.length; j++ (lastArray[j] == || lastArray[j].equals(""
lastFlag = } lastFlag = (! (indexFlag && }
(str == || str.equals("" j = 0 ( i = 0; i < str.length(); i++ ((str.charAt(i) >= 'a' && str.charAt(i) <= 'z' || (str.charAt(i) >= 'A' && str.charAt(i) <= 'Z' j = j + 1 (j ==
(str == || str.equals("" flag = ( i = 0; i < str.length(); i++ ((str.charAt(i) < 'a' || str.charAt(i) > 'z' && (str.charAt(i) < 'A' || str.charAt(i) > 'Z' flag = |