java – 如何对字符串进行排序,以便首先显示带有额外信息的值?
发布时间:2020-12-14 06:04:02 所属栏目:Java 来源:网络整理
导读:我试图排序以下字符串 1.0.0.0-00000000-000002.1.0.02.2.0.02.3.0.0-00000000-00000 我目前在一个字符串数组中有这些值. String[] arrays = {"1.0.0.0-00000000-00000","2.1.0.0","2.2.0.0","2.3.0.0-00000000-00000"}; 我试图有一个输出,如果没有“ – ”
我试图排序以下字符串
1.0.0.0-00000000-00000 2.1.0.0 2.2.0.0 2.3.0.0-00000000-00000 我目前在一个字符串数组中有这些值. String[] arrays = {"1.0.0.0-00000000-00000","2.1.0.0","2.2.0.0","2.3.0.0-00000000-00000"}; 我试图有一个输出,如果没有“ – ”那么这些值按排序顺序到达我的数组的末尾.我想要输出如下: 1.0.0.0-00000000-00000 2.3.0.0-00000000-00000 2.1.0.0 2.2.0.0 我试过Arrays.sort(数组),但我不确定如何对它进行排序? import java.util.Arrays; import java.util.Comparator; import java.util.Collections; public class HelloWorld{ public static void main(String []args){ String[] arrays = {"1.0.0.0-00000000-00000","2.3.0.0-00000000-00000"}; String[] newArray = new String[arrays.length]; class CustomComparator implements Comparator<String> { @Override public int compare(String a,String b) { if(a.contains("-") && !b.contains("-")) return 1; else if(!a.contains("-") && b.contains("-")) return -1; return a.compareTo(b); } } Arrays.sort(arrays,new CustomComparator()); for(String array : arrays) { System.out.println(array); } } } Error: $javac HelloWorld.java 2>&1 HelloWorld.java:25: error: no suitable method found for sort(String[],CustomComparator) Collections.sort(arrays,new CustomComparator()); ^ method Collections.<T#1>sort(List<T#1>,Comparator<? super T#1>) is not applicable (no instance(s) of type variable(s) T#1 exist so that argument type String[] conforms to formal parameter type List<T#1>) method Collections.<T#2>sort(List<T#2>) is not applicable (cannot instantiate from arguments because actual and formal argument lists differ in length) where T#1,T#2 are type-variables: T#1 extends Object declared in method <T#1>sort(List<T#1>,Comparator<? super T#1>) T#2 extends Comparable<? super T#2> declared in method <T#2>sort(List<T#2>) 1 error The method gave me an output of 2.1.0.0 2.2.0.0 1.0.0.0-00000000-00000 2.3.0.0-00000000-00000 as opposed to 1.0.0.0-00000000-00000 2.3.0.0-00000000-00000 2.1.0.0 2.2.0.0 解决方法
使用比较器
import java.util.Comparator; class CustomComparator implements Comparator<String> { @Override public int compare(String a,String b) { if(a.contains("-") && !b.contains("-")) return 1; else if(!a.contains("-") && b.contains("-")) return -1; return a.compareTo(b); } } Collections.sort(arrays,new CustomComparator()); 返回负值表示b在a之前,而正值表示a在b之前 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |