java – 从httppost响应中解析xml
发布时间:2020-12-14 05:58:22 所属栏目:Java 来源:网络整理
导读:在执行http POST期间,我将响应存储为String响应. HttpResponse httpresponse = httpclient.execute(httppost);HttpEntity resEntity = httpresponse.getEntity();response = EntityUtils.toString(resEntity); 如果我打印响应,它看起来像: ?xml version="1.
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在执行http POST期间,我将响应存储为String响应.
HttpResponse httpresponse = httpclient.execute(httppost); HttpEntity resEntity = httpresponse.getEntity(); response = EntityUtils.toString(resEntity); 如果我打印响应,它看起来像: <?xml version="1.0" encoding="UTF-8"?> <response status="ok"> <sessionID>lo8mdn7bientr71b5kn1kote90</sessionID> </response> 我想将sessionID存储为字符串.我试过了 DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); InputSource is = new InputSource(new StringReader(xml)); 和这样的各种方法,但它不会让我运行代码,因为DocumentBuildFactory和InputSource是无效的. 我应该怎么做才能从这个XML中提取特定的字符串? 解决方法
这只是快速而肮脏的测试.它对我有用.
import java.io.IOException;
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class Test {
public static void main(String[] args) {
String xml= "<?xml version="1.0" encoding="UTF-8"?><response status="ok"><sessionID>lo8mdn7bientr71b5kn1kote90</sessionID></response>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
InputSource is;
try {
builder = factory.newDocumentBuilder();
is = new InputSource(new StringReader(xml));
Document doc = builder.parse(is);
NodeList list = doc.getElementsByTagName("sessionID");
System.out.println(list.item(0).getTextContent());
} catch (ParserConfigurationException e) {
} catch (SAXException e) {
} catch (IOException e) {
}
}
}
输出:lo8mdn7bientr71b5kn1kote90 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
