[Ljava.lang.Object;不能被抛弃

发布时间：2020-12-14 05:31:27 所属栏目：Java 来源：网络整理

导读：我想从数据库获取值,在我的情况下,我使用List从数据库中获取值,但是我收到此错误 Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to id.co.bni.switcherservice.model.SwitcherServiceSourceat id.co.bni.sw

我想从数据库获取值,在我的情况下,我使用List从数据库中获取值,但是我收到此错误

Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to id.co.bni.switcherservice.model.SwitcherServiceSource
at id.co.bni.switcherservice.controller.SwitcherServiceController.LoadData(SwitcherServiceController.java:48)
at id.co.bni.switcherservice.controller.SwitcherServiceController.main(SwitcherServiceController.java:62)

这是我的代码

Query LoadSource = session_source.createQuery("select CLIENT,SERVICE,SERVICE_TYPE,PROVIDER_CODE,COUNT(*) FROM SwitcherServiceSource" +
            " where TIMESTAMP between :awal and :akhir" +
            " and PROVIDER_CODE is not null group by CLIENT,PROVIDER_CODE order by CLIENT,PROVIDER_CODE");
    LoadSource.setParameter("awal",fromDate);
    LoadSource.setParameter("akhir",toDate);

    List<SwitcherServiceSource> result_source = (List<SwitcherServiceSource>) LoadSource.list();
    for(SwitcherServiceSource tes : result_source){
        System.out.println(tes.getSERVICE());
    }

任何帮助将是快乐:)

@raffian,你的意思是这样吗？

List<Switcher> result = (List<Switcher>) LoadSource.list();
for(Switcher tes : result){
    System.out.println(tes.getSERVICE());
}

解决方法

java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to id.co.bni.switcherservice.model.SwitcherServiceSource

问题是

(List<SwitcherServiceSource>) LoadSource.list();

这将返回一个对象数组列表(Object []),其中包含SwitcherServiceSource表中每列的标量值. Hibernate将使用ResultSetMetadata来推导返回的标量值的实际顺序和类型.

解

List<Object> result = (List<Object>) LoadSource.list(); 
Iterator itr = result.iterator();
while(itr.hasNext()){
   Object[] obj = (Object[]) itr.next();
   //now you have one array of Object for each row
   String client = String.valueOf(obj[0]); // don't know the type of column CLIENT assuming String 
   Integer service = Integer.parseInt(String.valueOf(obj[1])); //SERVICE assumed as int
   //same way for all obj[2],obj[3],obj[4]
}