当1024字符是分隔符时,Java Scanner类在标记化时失败

如果我考虑一个字符串“a [* 1022]”“; [* n]”我期待一个n号令牌.
但是如果n = 3,则Scanner类失败：它“看到”只有2个令牌而不是3个.我认为它与Scanner类的内部char缓冲区大小有关.

a[x1022];      -> 1 token: correct

a[x1022];;     -> 2 token: correct

a[x1022];;;    -> 2 token: wrong  (I expect 3 tokens)

a[x1022];;;;   -> 4 token: correct

我附上一个简单的例子：

import java.util.Scanner;

public static void main(String[] args) {

    // generate test string: (1022x "a") + (3x ";") 
    String testLine = "";
    for (int i = 0; i < 1022; i++) {
        testLine = testLine + "a";
    }
    testLine = testLine + ";;;";

    // set up the Scanner variable
    String delimeter = ";";
    Scanner lineScanner = new Scanner(testLine);
    lineScanner.useDelimiter(delimeter);
    int p = 0;

    // tokenization
    while (lineScanner.hasNext()){
            p++;
            String currentToken = lineScanner.next();
            System.out.println("token" + p +  ": '" + currentToken + "'");
    }
    lineScanner.close();
}

我想跳过“不正确”的行为,你能帮帮我吗？
谢谢