PHP编程:php实现高效获取图片尺寸的方法
发布时间:2020-12-13 02:15:49 所属栏目:PHP教程 来源:网络整理
导读:《php实现高效获取图片尺寸的方法》要点: 本文介绍了php实现高效获取图片尺寸的方法,希望对您有用。如果有疑问,可以联系我们。 PHP实战 本篇章节讲解php实现高效获取图片尺寸的办法.供大家参考研究.具体分析如下: PHP实战 php 获取图片尺寸的办
《php实现高效获取图片尺寸的方法》要点: PHP实战本篇章节讲解php实现高效获取图片尺寸的办法.分享给大家供大家参考.具体分析如下: PHP实战php 获取图片尺寸的办法我们可以使用 getimagesize 获取图片尺寸,但是效率是很低的,首先需要获取整个的图片信息,然后再进行操作,下面的例子更科学算法更好,我们一起来看看吧. PHP实战办法可以用于快速获取图片尺寸信息,获取JPEG格式图片的尺寸信息,并且不需要下载读取整个图片,经测试这个函数不是对所有JPEG格式的图片都有效. PHP实战1.获取JPEG格式图片的尺寸信息,代码如下:
代码如下:
<?php
/* * */ ? // Retrieve JPEG width and height without downloading/reading entire image. function getjpegsize($img_loc) { ??? $handle = fopen($img_loc,"rb") or die("Invalid file stream."); ??? $new_block = NULL; ??? if(!feof($handle)) { ??????? $new_block = fread($handle,32); ??????? $i = 0; ??????? if($new_block[$i]=="xFF" && $new_block[$i+1]=="xD8" && $new_block[$i+2]=="xFF" && $new_block[$i+3]=="xE0") { ??????????? $i += 4; ??????????? if($new_block[$i+2]=="x4A" && $new_block[$i+3]=="x46" && $new_block[$i+4]=="x49" && $new_block[$i+5]=="x46" && $new_block[$i+6]=="x00") { ???????????????? // Read block size and skip ahead to begin cycling through blocks in search of SOF marker ? ??????????????? $block_size = unpack("H*",$new_block[$i] . $new_block[$i+1]); ??????????????? $block_size = hexdec($block_size[1]); ??????????????? while(!feof($handle)) { ??????????????????? $i += $block_size; ??????????????????? $new_block .= fread($handle,$block_size); ??????????????????? if($new_block[$i]=="xFF") { ???????????????????????? // New block detected,check for SOF marker ? ??????????????????????? $sof_marker = array("xC0","xC1","xC2","xC3","xC5","xC6","xC7","xC8","xC9","xCA","xCB","xCD","xCE","xCF"); ??????????????????????? if(in_array($new_block[$i+1],$sof_marker)) { ???????????????????????????? // SOF marker detected. Width and height information is contained in bytes 4-7 after this byte. ? ??????????????????????????? $size_data = $new_block[$i+2] . $new_block[$i+3] . $new_block[$i+4] . $new_block[$i+5] . $new_block[$i+6] . $new_block[$i+7] . $new_block[$i+8]; ??????????????????????????? $unpacked = unpack("H*",$size_data); ??????????????????????????? $unpacked = $unpacked[1]; ??????????????????????????? $height = hexdec($unpacked[6] . $unpacked[7] . $unpacked[8] . $unpacked[9]); ??????????????????????????? $width = hexdec($unpacked[10] . $unpacked[11] . $unpacked[12] . $unpacked[13]); ??????????????????????????? return array($width,$height); ??????????????????????? } else { ???????????????????????????? // Skip block marker and read block size ? ??????????????????????????? $i += 2; ??????????????????????????? $block_size = unpack("H*",$new_block[$i] . $new_block[$i+1]); ??????????????????????????? $block_size = hexdec($block_size[1]); ??????????????????????? } ??????????????????? } else { ??????????????????????? return FALSE; ??????????????????? } ??????????????? } ??????????? } ??????? } ??? } ??? return FALSE; } ?> 2.实例代码如下:
代码如下:
$url='http://www.xxxx.com/images/1331189004_28093400.jpg';
$image_content = file_get_contents($url); $image = imagecreatefromstring($image_content); $width = imagesx($image); $height = imagesy($image); echo $width.'*'.$height."nr"; PHP实战希望本文所述对大家的PHP程序设计有所赞助. 欢迎参与《php实现高效获取图片尺寸的方法》讨论,分享您的想法,编程之家 52php.cn为您提供专业教程。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |