php – simpleXML基于属性获取节点子节点
发布时间:2020-12-13 22:22:40 所属栏目:PHP教程 来源:网络整理
导读:参见英文答案 SimpleXML: Selecting Elements Which Have A Certain Attribute Value????????????????????????????????????2个 ???????????? Implementing condition in XPath ????????????????????????????????????2个 我试图通过其中一个属性解析我引用的
参见英文答案 >
SimpleXML: Selecting Elements Which Have A Certain Attribute Value????????????????????????????????????2个
>???????????? Implementing condition in XPath ????????????????????????????????????2个 我试图通过其中一个属性解析我引用的节点的值.但我不确定语法 XML: <data> <poster name="E-Verify" id="everify"> <full_image url="e-verify-swa-poster.jpg"/> <full_other url=""/> </poster> <poster name="Minimum Wage" id="minwage"> <full_image url="minwage.jpg"/> <full_other url="spa_minwage.jpg"/> </poster> </data> 这里是我想要获取full_image的url值,其中poster id等于minwage: $xml = simplexml_load_file('PosterData.xml'); $main_url = $xml->full_image[name] where poster[id] = "minwage"; //something like that. echo $main_url; Result: minwage.jpg 如果有人有任何资源涵盖这些东西请分享. 解决方法
只需循环播放海报元素并记住将属性值强制转换为字符串,因为您希望将它们(并可能将它们输出)作为字符串进行比较:
$xml = simplexml_load_file('PosterData.xml'); foreach ($xml->poster as $poster) { if ((string) $poster['id'] == 'minwage') { echo (string) $poster->full_image['url']; } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |