如何调用php文件发送邮件？ ,Android

发布时间：2020-12-13 17:18:39 所属栏目：PHP教程来源：网络整理

导读：我有以下mail.php文件： ?php$name = $_POST['name'];$to = $_POST['to'];$from = $_POST['from'];$subject = $_POST['subject'];$message = "From: ".$name."rn";$message .= $_POST['message'];$headers = "From:" . $from;mail($to,$subject,$message,$

我有以下mail.php文件：

<?php
$name = $_POST['name'];
$to = $_POST['to'];
$from = $_POST['from'];
$subject = $_POST['subject'];
$message = "From: ".$name."rn";
$message .= $_POST['message'];
$headers = "From:" . $from;
mail($to,$subject,$message,$headers);
?>

我有以下布局从我的应用程序发送邮件：

我想在点击发送按钮后发送邮件到静态邮件,例如：mymail@mail.com.
如何通过调用上面的php文件发送邮件.
我听说过调用上面的php文件的post方法
但是对它没有任何想法.
请帮忙！

解决方法

这里是：

public static void sendData(String name,String to,String from,String subject,String message)
    {
        String content = "";

        try
        {               
            /* Sends data through a HTTP POST request */
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("http://your.website.com");
            List <NameValuePair> params = new ArrayList <NameValuePair>();
            params.add(new BasicNameValuePair("name",name));
            params.add(new BasicNameValuePair("to",to));
            params.add(new BasicNameValuePair("from",from));
            params.add(new BasicNameValuePair("subject",subject));
            params.add(new BasicNameValuePair("message",message));
            httpPost.setEntity(new UrlEncodedFormEntity(params,HTTP.UTF_8));

            /* Reads the server response */
            HttpResponse response = httpClient.execute(httpPost);
            InputStream in = response.getEntity().getContent();

            StringBuffer sb = new StringBuffer();
            int chr;
            while ((chr = in.read()) != -1)
            {
                sb.append((char) chr);
            }
            content = sb.toString();
            in.close();

            /* If there is a response,display it */
            if (!content.equals(""))
            {
                Log.i("HTTP Response",content);
            }
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
    }

（编辑：李大同）

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