对我的第一个项目PHP类的建议/建议

你有什么想法,你将如何实现如form-> validate-> insertquery-> sendmail->返回消息和错误这样的任务？

请尽量让你的答案足够简单,让我能够理解它对于理解最新情况,而不仅仅是复制/粘贴工作.

最亲切的问候,
菲尔.

注意：这只是一个基本结构,没有添加完整的代码.

<?php
//=======================================
    //class.logging.php
//========================================
    class logging
    {

        public $data = array();
        public $errors = array();



        function __construct()
        {
            array_pop($_POST);
            $this->data =($this->_logging)? is_isset(filterStr($_POST) : '';

            foreach($this->data as $key=> $value)
            {
                $this->data[$key] = $value; 
            }
            //print_r($this->data); de-bugging
        }

        public function is_isset($str)
        {
            if(isset($str)) ? true: false;
        }

        public function filterStr($str)
        {
            return preg_match(do somthing,$str);
        }

        public function validate_post()
        {
            try
            {
                if(!is_numeric($data['cardID'])) ? throw new Exception('CardID must be numeric!') : continue;   
            }
            catch (Exception $e)
            {

                return $errors = $e->getCode();
            }
        }

        public function showErrors()
        {
            foreach($errors as $error => $err)
            {
                print('<div class="notok"></div><br />');
            }
        }

        public function insertQ()
        {
            $query = "";
        }

    }


//=======================================
    //Usercp.php
//========================================
if(isset($_GET['mode']))
     {
     $mode = $_GET['mode'];
     }
     else
     {
     $mode = 'usercp';
     }


     switch($mode)
    {
        case 'usercp':
        echo 'Welcome to the User Control Panel';
        break;

        case 'logging':
            require_once 'class.logging.php';
            $logger = new logging();

            if(isset($_POST['submit'])
            {
                if($logger->validate_post === true)
                {
                    $logger->insertQ();
                    require_once '/scripts/PHPMailer/class.phpmailer.php';
                    $mailer = new PHPMailer();
                    $mailer->PHPMailer();
                }
                else
                {
                    echo ''.$logger->showErrors.''; 
                }
            }
            else
            {
                echo 
                    '
                    <form action="'.$_SERVER['PHP_SELF'].'?mode=logging" method="post">

                    </form>
                    ';  
            }
        break;

        case 'user_logout':
        // do somthing
        break;

        case 'user_settings':
        // do somthing
        break;






?>

我已决定使用此方法返回错误而不是在方法中打印它们,感谢Igor的建议！

catch (Exception $e)
            {
                $this->errors[] = $e->getMessage();

            #ERROR DE_BUGGING ONLY================================
            #print('<pre>');
                    #print_r($this->errors); 
            #print('</pre>');
            #=====================================================
            }
            if($this->errors)
            {
                return false;
            }
            else
            {
                return true;    
            }