PHP array_keys – 我做错了什么?
发布时间:2020-12-13 16:11:49 所属栏目:PHP教程 来源:网络整理
导读:我有两个数组: $字段名: array([0] = array( ['fieldName'] ='id' ['fieldType'] = 'int(11)' )[1] = ['fieldName'] ='adminID' ['fieldType'] ='int(11)' )[2] =array( ['fieldName'] ='schoolID' ['fieldType'] ='int(11)' )[3] = array( ['fieldName']
我有两个数组:
$字段名: array( [0] => array( ['fieldName'] =>'id' ['fieldType'] => 'int(11)' ) [1] => ['fieldName'] =>'adminID' ['fieldType'] =>'int(11)' ) [2] =>array( ['fieldName'] =>'schoolID' ['fieldType'] =>'int(11)' ) [3] => array( ['fieldName'] =>'lessonPlanName' ['fieldType'] =>'varchar(255)' ) [4] =>array( ['fieldName'] =>'lessonPlanAssignmentDate' ['fieldType'] =>'varchar(255)' ) [5] =>array( ['fieldName'] =>'lessonPlanDueDate' ['fieldType'] =>'varchar(255)' ) [6] =>array( ['fieldName'] =>'lessonPlanTopics' ['fieldType'] =>'varchar(255)' ) [7] =>array( ['fieldName'] =>'lessonPlanDescription' ['fieldType'] =>'text' ) [8] =>array( ['fieldName'] =>'lessonPlanNotes' ['fieldType'] =>'text' ) ) $formElementPairs: array( ['lessonPlanName'] =>'Test' ['lessonPlanAssignedDate'] =>'05/11/2011' ['lessonPlanDueDate'] =>'05/11/2011' ['lessonPlanTopics'] => 1 ['lessonPlanDescription'] =>'test' ) 我正在尝试检查数组2是否缺少数组1中的任何’fieldName’键,然后将它们添加到带有空条目的数组2中.以下代码的工作原理是我从第一个数组(id,adminId,schoolId等)获取“fieldName”值,但是当我使用array_keys检查第二个数组时,我得到的数组总是有一个0.还应该提到我在这个项目中使用PHP4. //merge arrays for($fn=0; $fn<count($fieldNames); $fn++) { $thisFieldName = $fieldNames[$fn]['fieldName']; $fieldCheckArray = array_keys($formElementPairs,$thisFieldName); //$firephp->fb(count($fieldCheckArray)); } 我是否误解了array_keys和/或是否有更优雅的方法在PHP4中执行此操作? 谢谢 解决方法
您可以使用array_key_exists检查数组2是否缺少任何内容:
array_key_exists $missing = array(); for($fn=0; $fn<count($fieldNames); $fn++) { $thisFieldName = $fieldNames[$fn]['fieldName']; if(!array_key_exists($thisFieldName,$formElementPairs)) { $missing[] = $thisFieldName; } } //do something with $missing (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |