[VB.NET]OpenFileDialog问题
发布时间：2020-12-16 23:46:07 所属栏目：大数据 来源：网络整理
导读：OpenFileDialog问题 If OpenFileDialog1.ShowDialog = DialogResult.Cancel Then Exit Sub End If 请问为什么两次点击取消才能取消，而savefiledialog确没有问题， 请问如何解决谢谢 _____________________________________________________________________
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OpenFileDialog问题 If OpenFileDialog1.ShowDialog = DialogResult.Cancel Then Exit Sub End If 请问为什么两次点击取消才能取消，而savefiledialog确没有问题， 请问如何解决谢谢 __________________________________________________________________________ If OpenFileDialog1.ShowDialog = Windows.Forms.DialogResult.Cancel Then Exit Sub End If 应该不是这三行的问题，请多贴些代码。 __________________________________________________________________________ Try Dim myreader = New System.IO.StreamReader(myfilename,System.Text.Encoding.Default) Dim myreceiver As String = myreader.readline While Not myreceiver Is Nothing RichTextBox1.AppendText(myreceiver & vbCrLf) myreceiver = myreader.readline End While Catch ex As Exception MessageBox.Show(ex.Message,"error ",MessageBoxButtons.OK,MessageBoxIcon.Information) End Try 感谢楼上确实因为上面的代码，应怎样改呢？ __________________________________________________________________________ 可能需要filname的定义和赋值部分。 __________________________________________________________________________ 我是说myfilename。 __________________________________________________________________________ Dim result As DialogResult With Me.OpenFileDialog1 .Title = "Open " .CheckFileExists = True .CheckPathExists = True .Filter = "all(*.txt)|*.txt " .ShowDialog() myfilename = .FileName End With If result = OpenFileDialog1.ShowDialog.Cancel Then ''If OpenFileDialog1.ShowDialog = DialogResult.Cancel Then Exit Sub End If RichTextBox1.Text = " " Try Dim myreader = New System.IO.StreamReader(myfilename,MessageBoxIcon.Information) End Try __________________________________________________________________________ 我上面用了两种判断效果都一样，自己试了是由于 Dim myreader = New System.IO.StreamReader(myfilename,System.Text.Encoding.Default) 此部分要求文件名不能为空，所引起的，不知道怎么解决 __________________________________________________________________________ 您用了两次ShowDialog，所以会出现两次，（在判断时用ShowDialog和在别处用是一样的） 我帮您把代码改了一下，容易看些： Public Class Form1 Private Sub Button1_Click(ByVal sender As Object,ByVal e As System.EventArgs) Handles Button1.Click Dim myfilename As String = " " With Me.OpenFileDialog1 .Title = "Open " .CheckFileExists = True .CheckPathExists = True .Filter = "all(*.txt)|*.txt " .FileName = " " End With If OpenFileDialog1.ShowDialog = Windows.Forms.DialogResult.OK Then RichTextBox1.Text = " " myfilename = Me.OpenFileDialog1.FileName Try Dim myreader = New System.IO.StreamReader(myfilename,MessageBoxIcon.Information) End Try End If End Sub End Class __________________________________________________________________________ 谢谢我也发现这个问题了，非常感谢 __________________________________________________________________________ 赶时间忙得头脑发热了哈哈 __________________________________________________________________________ （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |