perl脚本的目录

http://stackoverflow.com/questions/5703705/print-current-directory-using-perl?rq=1

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1）

The following get the script's directory,which is not the same as the current directory. It's not clear which one you want.

use Cwd qw( abs_path );

useFile::Basename qw( dirname ); say dirname(abs_path($0));

or

usePath::Class qw( file ); say file($0)->absolute->dir;

or

useCwd qw( abs_path );

use Path::Class qw( file ); say file(abs_path($0))->dir;

The middle one handles symlinks different than the other two,I believe.

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2）

To get the current working directory (pwd on many systems),you could use cwd() instead of abs_path:

useCwd qw();

my $path =Cwd::cwd();

print "$pathn";

Or abs_path without an argument:

useCwd qw();

my $path =Cwd::abs_path();

print "$pathn";

See the?Cwd docs?for details.

To get the directory your perl file is in from outside of the directory:

useFile::Basename qw();

my($name, $path, $suffix)=File::Basename::fileparse($0);

print "$pathn";

See the?File::Basename?docs for more details.

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3）

You could use?FindBin:

use FindBin '$RealBin';

print "$RealBinn";

FindBin?is a standard module that is installed when you install Perl. To get a list of the standard pragmatics and modules,see?perldoc perlmodlib.

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完！