当我在Perl中从自身中减去相同的浮点数时,为什么不能得到零?
发布时间:2020-12-15 21:16:18 所属栏目:大数据 来源:网络整理
导读:Possible Duplicates: 07000 07001 #!/usr/bin/perl$l1 = "0+0.590580+0.583742+0.579787+0.564928+0.504538+0.459805+0.433273+0.384211+0.3035810";$l2 = "0+0.590580+0.583742+0.579788+0.564928+0.504538+0.459805+0.433272+0.384211+0.3035810";$val1 =
#!/usr/bin/perl $l1 = "0+0.590580+0.583742+0.579787+0.564928+0.504538+0.459805+0.433273+0.384211+0.3035810"; $l2 = "0+0.590580+0.583742+0.579788+0.564928+0.504538+0.459805+0.433272+0.384211+0.3035810"; $val1 = eval ($l1); $val2 = eval ($l2); $diff = (($val1 - $val2)/$val1)*100; print " (($val1 - $val2)/$val1)*100 ==> $diffn"; 令人惊讶的是,输出最终结果是 ((4.404445 - 4.404445)/4.404445)*100 ==> -2.01655014354845e-14. 它不应该是一个零吗???? 解决方法
What every computer scientist should know about floating point arithmetic
见Why is floating point arithmetic in C# imprecise? 这与Perl无关,但浮点相关. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |