Perl格式化输出时间日期

方法一：

use POSIX qw(strftime);

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my $timeStr1 = strftime "%Y-%m-%d",localtime;

my $timeStr2 = strftime "%Y-%m-%d",localtime(time-86400); （前一天）

print "$timeStr n";

方法二：

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#!/usr/bin/perl
 
($sec,$min,$hour,$day,$mon,$year,$weekday,$yeardate,$savinglightday)
  = (localtime(time));
 
$sec  = ($sec < 10)? "0$sec":$sec;
$min  = ($min < 10)? "0$min":$min;
$hour = ($hour < 10)? "0$hour":$hour;
$day  = ($day < 10)? "0$day":$day;
$mon  = ($mon < 9)? "0".($mon+1):($mon+1);
$year += 1900;
 
$today = "$day.$mon.$year|$hour:$min:$sec";
 
print $today."n";
print time."n";
 
 
 
 
 
如果要输出一天前的日期，将time减去一天的秒数（86400）。
 
(localtime(time-86400));
 
 
 
 
#!/usr/bin/perl
 
print &get_time(10)."n";
 
sub get_time {
  
  $interval = $_[0]*60;
  
  ($sec,$savinglightday)
    = (localtime(time + $interval));
 
  $sec  = ($sec < 10)? "0$sec":$sec;
  $min  = ($min < 10)? "0$min":$min;
  $hour = ($hour < 10)? "0$hour":$hour;
  $day  = ($day < 10)? "0$day":$day;
  $mon  = ($mon < 9)? "0".($mon+1):($mon+1);
  $year += 1900;
  
  return "$year-$mon-$day $hour:$min:$sec.00";
  
}
 
 
 
sub getTime(){
 (my $sec,my $min,my $hour,my $day,my $mon,my $year,my $weekday,my $yeardate,my $savinglightday)
= (localtime(time));
 $sec = ($sec < 10)? "0$sec":$sec;
 $min = ($min < 10)? "0$min":$min;
 $hour = ($hour < 10)? "0$hour":$hour;
 $day = ($day < 10)? "0$day":$day;
 $mon = ($mon < 9)? "0".($mon+1):($mon+1);
 $year += 1900;
 
 my $now = "$year$mon$day $hour:$min:$sec ";
 return $now;
}