我正在使用在activator上发布的Spring Akka示例来创建Spring托管bean演员.这是我目前正在使用的代码,包括一个演示类：
@Component
class Test extends UntypedActor {
@Autowired
protected ObjectMapper objectMapper;
protected final Account account;
protected final Order order;
public Test(Account account,Order order) {
this.account = account;
this.order = order;
}
@Override
public void onReceive(Object message) throws Exception {
if (message instanceof SomeCommand) {
// Do something using the order and the account;
} else if (message instanceof FooCommand) {
// More stuff
}
}
}
@Component
public class SpringExtension extends AbstractExtensionId
现在我的问题是,如何用自定义构造函数参数实例化一个actor.我曾考虑使用工厂或setter方法,但我不认为这是一个选项,因为我相信底层的Actor类是不可访问的.关于此事的任何意见都非常感谢.如果现在有问题,请发表评论.
PS.如果您认为我的代码中存在错误或有更好的解决方法,请告诉我！我对Spring和Akka的经验很少,所以任何建议都表示赞赏. 最佳答案
您可以将其他参数作为varargs(Object …)传递给SpringExtensionImpl和SpringActorProducer.所以你的代码看起来像这样：
@Component
public class SpringExtensionImpl implements Extension {
@Autowired
private ApplicationContext applicationContext;
public Props props(String actorBeanName,Object... args) {
return (args != null && args.length > 0) ?
Props.create(SpringActorProducer.class,actorBeanName,args) :
Props.create(SpringActorProducer.class,actorBeanName);
}
}
public class SpringActorProducer implements IndirectActorProducer {
private final ApplicationContext applicationContext;
private final String actorBeanName;
private final Object[] args;
public SpringActorProducer(ApplicationContext applicationContext,String actorBeanName) {
this.applicationContext = applicationContext;
this.actorBeanName = actorBeanName;
this.args = null;
}
public SpringActorProducer(ApplicationContext applicationContext,String actorBeanName,Object... args) {
this.applicationContext = applicationContext;
this.actorBeanName = actorBeanName;
this.args = args;
}
@Override
public Actor produce() {
return args == null ?
(Actor) applicationContext.getBean(actorBeanName):
(Actor) applicationContext.getBean(actorBeanName,args);
}
@Override
public Class
然后,您可以像这样创建Test actor：
SpringExtensionImpl springExtensionImpl;
actorSystem.actorOf(springExtensionImpl.create(Test.class,account,order)); （编辑：李大同）
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