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php – 如何在Laravel Auth :: attempt中使用条件参数?

发布时间:2020-12-14 19:44:08 所属栏目:大数据 来源:网络整理
导读:使用Laravel 4.1.30我得到以下代码,通过Auth测试登录尝试. //... more codes here ...$auth = Auth::attempt(array( 'email' = Input::get('email'),'password' = Input::get('password'),'active' = 1),$remember);if ($auth) { //... more codes here ...}
使用Laravel 4.1.30我得到以下代码,通过Auth测试登录尝试.

//... more codes here ...

$auth = Auth::attempt(array(
    'email'     => Input::get('email'),'password'  => Input::get('password'),'active'    => 1
),$remember);

if ($auth) {
    //... more codes here ...
}

我想实现一个条件值,例如:

->active > 0

我使用活动(字段)作为登录用户的身份验证级别.任何高于0(零)的内容都应满足下一个条件.

怎么能在一个声明中完成?

解决方法

TL;博士

您不能在传递给Auth :: attempt()的数组中执行此操作,因为在框架中,硬编码在生成的查询中使用相等比较.

全面审查

框架实施

attempt()函数在Illuminate / Auth / Guard.php中实现.

public function attempt(array $credentials = array(),$remember = false,$login = true)
{
    $this->fireAttemptEvent($credentials,$remember,$login);

    $this->lastAttempted = $user = $this->provider->retrieveByCredentials($credentials);

    // If an implementation of UserInterface was returned,we'll ask the provider
    // to validate the user against the given credentials,and if they are in
    // fact valid we'll log the users into the application and return true.
    if ($this->hasValidCredentials($user,$credentials))
    {
        if ($login) $this->login($user,$remember);

        return true;
    }

    return false;
}

在这里,您可以看到$this-> provider-> retrieveByCredentials($credentials);的电话. retrieveByCredentials()函数在Illuminate / Auth / DatabaseUserProvider.php中实现.

public function retrieveByCredentials(array $credentials)
{
    // First we will add each credential element to the query as a where clause.
    // Then we can execute the query and,if we found a user,return it in a
    // generic "user" object that will be utilized by the Guard instances.
    $query = $this->conn->table($this->table);

    foreach ($credentials as $key => $value)
    {
        if ( ! str_contains($key,'password'))
        {
            $query->where($key,$value);
        }
    }

    // Now we are ready to execute the query to see if we have an user matching
    // the given credentials. If not,we will just return nulls and indicate
    // that there are no matching users for these given credential arrays.
    $user = $query->first();

    if ( ! is_null($user))
    {
        return new GenericUser((array) $user);
    }
}

在这里,您可以看到传递给Auth :: attempt()的数组在foreach中处理,并且每个键值对都作为WHERE子句添加到查询中.因为它完成了$query-> where($key,$value);打电话,它仅限于平等比较.

可能的解决方案

解决方法是将此行更改为:

$query->where($key,$value['operator'],$value['value']);

然后你可以重构给Auth :: attempt()的数组.

$auth = Auth::attempt(array(
    'email' => array(
        'value'    => Input::get('email'),'operator' => '='
    ),'password' => array(
        'value'    => Input::get('password'),'active' => array(
        'value'    => 0,'operator' => '>'
    )
),$remember);

这个问题是你必须覆盖使用这个数组的所有其他函数,所以你最终得到了一个自定义解决方案.通过这种努力,您可以编写自己的身份验证查询,或者在Auth :: attempt()之后检查是否处于活动状态.

(编辑:李大同)

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