Numerical Analysis
发布时间:2020-12-14 05:14:10 所属栏目:大数据 来源:网络整理
导读:PART1? 求解方程 1,二分法 def bisect(f,a,b,TOL= 0.000004 ): u_a = a u_b = b while (u_b-u_a)/ 2.0 TOL: c = (u_a+u_b)/ 2.0 if f(c) == 0 : break if f(u_a)*f(c) 0 : u_b = c else : u_a = c u_c = (u_a + u_b) / 2.0 return u_cf = lambda x: x*x*x +
PART1? <求解方程> 1,二分法 def bisect(f,a,b,TOL=0.000004): u_a = a u_b = b while(u_b-u_a)/2.0 > TOL: c = (u_a+u_b)/2.0 if f(c) == 0: break if f(u_a)*f(c) < 0: u_b = c else: u_a = c u_c = (u_a + u_b) / 2.0 return u_c f = lambda x: x*x*x + x - 1 ret = bisect(f,-1.0,1.0) print(ret) print(f(ret)) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |