I have a very simple problem for you. Given two integers A and B,your job is to calculate the Sum of A + B.

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow,each line consists of two positive integers,A and B. Notice that the integers are very large,that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

For each test case,you should output two lines. The first line is "Case #:",# means the number of the test case. The second line is the an equation "A + B = Sum",Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

  
  

   
   2
1 2
112233445566778899 998877665544332211
  
  

  
  

   
   Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 2222222222222221110
  
  

Ignatius.L

package hdu1002;

import java.util.*;
import java.math.*;

/**
 * 大数相加
 */
public class Main {
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in); // 定义一个输入流对象
		int t,flag = 0;
		BigInteger a,b,sum; // 定义大数
		t = cin.nextInt(); // 输入 t
		while ((t--) != 0) {
			if ((flag++) != 0) // 设置标志，实现行之间的空格
				System.out.println();
			a = cin.nextBigInteger(); // 输入大数a
			b = cin.nextBigInteger(); // 输入大数b
			sum = a.add(b); // 两个大数相加
			System.out.println("Case " + flag + ":");
			System.out.println(a + " + " + b + " = " + sum);
		}
	}
}