leetcode 235. Lowest Common Ancestor of a Binary Search Tree
发布时间:2020-12-14 04:49:18 所属栏目:大数据 来源:网络整理
导读:Given a binary search tree (BST),find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in
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Given a binary search tree (BST),find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).” Given binary search tree:? root =?[6,2,8,4,7,9,null,3,5] _______6______
/ ___2__ ___8__
/ / 0 _4 7 9
/ 3 5
Example 1: Input: root,p = 2,q = 8 Output: 6 Explanation: The LCA of nodes and is . 286 Example 2: Input: root,q = 4
Output: 2
Explanation: The LCA of nodes and is,since a node can be a descendant of itself
according to the LCA definition.
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self,x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def lowestCommonAncestor(self,root,p,q):
"""
:type root: TreeNode
:type p: TreeNode
:type q: TreeNode
:rtype: TreeNode
"""
node = root
while node:
if node.val in {p.val,q.val}:
return node
elif node.val > p.val and node.val > q.val:
node = node.left
elif node.val < p.val and node.val < q.val:
node = node.right
else:
return node
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