leetcode-easy-trees-102. Binary Tree Level Order Traversal-Y
发布时间:2020-12-14 04:44:22 所属栏目:大数据 来源:网络整理
导读:mycode? 98.56% # Definition for a binary tree node. # class TreeNode(object): # def __init__(self,x): # self.val = x # self.left = None # self.right = None class Solution(object): def levelOrder(self,root): """ :type root: TreeNode :rtype:
mycode? 98.56% # Definition for a binary tree node. # class TreeNode(object): # def __init__(self,x): # self.val = x # self.left = None # self.right = None class Solution(object): def levelOrder(self,root): """ :type root: TreeNode :rtype: List[List[int]] """ def deal(root,level): if not root: return if len(self.res) <= level: self.res.append([root.val]) else: self.res[level].append(root.val) deal(root.left,level+1) deal(root.right,level+1) self.res = [] deal(root,0) return self.res (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |