大数加法
发布时间:2020-12-14 03:27:49 所属栏目:大数据 来源:网络整理
导读:A -? 你会敲A+B吗? Time Limit: 1000 MS????? Memory Limit: 10000 KB????? 64bit IO Format: %I64d %I64u Submit ? Status ? Practice ? POJ 1503 Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his explo
A -?你会敲A+B吗?
Time Limit:1000MS?????Memory Limit:10000KB?????64bit IO Format:%I64d & %I64u
Description
One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers.?
``This supercomputer is great,'' remarked Chip. ``I only wish Timothy were here to see these results.'' (Chip moved to a new apartment,once one became available on the third floor of the Lemon Sky apartments on Third Street.)? Input
The input will consist of at most 100 lines of text,each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length,and will only contain digits (no VeryLongInteger will be negative).?
The final input line will contain a single zero on a line by itself.? Output
Your program should output the sum of the VeryLongIntegers given in the input.
Sample Input 123456789012345678901234567890 123456789012345678901234567890 123456789012345678901234567890 0 Sample Output 370370367037037036703703703670
代码张鑫提供 #include<stdio.h> #include<stdlib.h> #include<string.h> char a[1000]; int num[1000]; int main() { ? ? memset(num,sizeof(num)); ? ? int MAX=0,i; ? ? while(scanf("%s",a),strcmp(a,"0")) ? ? { ? ? ? ? if(strlen(a)>MAX) ? ? ? ? { ? ? ? ? ? ? MAX=strlen(a); ? ? ? ? } ? ? ? ? for(i=strlen(a)-1;i>=0;i--) ? ? ? ? { ? ? ? ? ? ? num[strlen(a)-1-i]+=a[i]-'0'; ? ? ? ? } ? ? ? ? for(i=0;i<(MAX+10);i++) ? ? ? ? { ? ? ? ? ? ? if(num[i]>9) ? ? ? ? ? ? { ? ? ? ? ? ? ? ? num[i+1]+=num[i]/10; ? ? ? ? ? ? ? ? num[i]=num[i]%10; ? ? ? ? ? ? } ? ? ? ? ? ? else ? ? ? ? ? ? { ? ? ? ? ? ? ? ? num[i]=num[i]; ? ? ? ? ? ? } ? ? ? ? } ? ? } ? ? int st; ? ? ? ? for(st=(MAX+10);st>=0;st--) ? ? ? ? { ? ? ? ? ? ? if(num[st]!=0) ? ? ? ? ? ? { ? ? ? ? ? ? ? ? break; ? ? ? ? ? ? } ? ? ? ? } ? ? ? ? if(st<0) ? ? ? ? { ? ? ? ? ? ? printf("0"); ? ? ? ? } ? ? ? ? else ? ? ? ? { ? ? ? ? ? ? for(i=st;i>=0;i--) ? ? ? ? ? ? { ? ? ? ? ? ? ? ? printf("%d",num[i]); ? ? ? ? ? ? } ? ? ? ? } ? ? ? ? printf("n"); ? ? return 0; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |