ruby-on-rails – 使用NOT与Squeel
发布时间:2020-12-17 03:38:22 所属栏目:百科 来源:网络整理
导读:说我有一套条件: Person.where{(name =~ 'Ernie%') (salary 50000) | (name =~ 'Joe%') (salary 100000)} …将生成如下SQL: SELECT "people".* FROM people WHERE ("people"."name" LIKE 'Ernie%' AND "people"."salary" 50000) OR ("people"."name" LIKE
说我有一套条件:
Person.where{(name =~ 'Ernie%') & (salary < 50000) | (name =~ 'Joe%') & (salary > 100000)} …将生成如下SQL: SELECT "people".* FROM people WHERE ("people"."name" LIKE 'Ernie%' AND "people"."salary" < 50000) OR ("people"."name" LIKE 'Joe%' AND "people"."salary" > 100000) 如何反转返回的集合,即更新Squeel以返回以下sql: SELECT "people".* FROM people WHERE NOT(("people"."name" LIKE 'Ernie%' AND "people"."salary" < 50000) OR ("people"."name" LIKE 'Joe%' AND "people"."salary" > 100000)) 这有点人为,因为我的问题还涉及一组动态生成的条件 – 我无法改变实际条件,只需要将它们包装在NOT()中. 任何关于在哪里寻找的想法或建议? 解决方法
你会想要使用一元减号运算符.
Person.where{-((name =~ 'Ernie%') & (salary < 50000) | (name =~ 'Joe%') & (salary > 100000))}.to_sql => "SELECT "people".* FROM "people" WHERE (NOT ((("people"."name" LIKE 'Ernie%' AND "people"."salary" < 50000) OR ("people"."name" LIKE 'Joe%' AND "people"."salary" > 100000))))" (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |