ruby-on-rails – 如何让will_paginate正确显示条目数？

简短的回答

您可以将模型选项指定为字符串,该字符串将正确复数.

page_entries_info @contracts,:model => 'contract'
# Displaying contracts 1 - 35 of 4825 in total

更长的答案

您使用the i18n mechanism定制输出的will_paginate docs suggest.这是一种痛苦,因为AFAICT你必须在config / locales / *.yml文件(例如,en.yml)中为所有模型写出单数和复数形式,并且％{foo} -style语法不会似乎是ERB,但只是占位符,所以你不能做像％{foo.downcase}这样的事情.

如果您编写自己的帮助程序,则可以完全控制输出.例如：

def my_page_info(collection)
  model_class = collection.first.class
  if model_class.respond_to? :model_name
    model = model_class.model_name.human.downcase
    models = model.pluralize
    if collection.total_entries == 0
      "No #{models} found."
    elsif collection.total_entries == 1
      "Found one #{model}."
    elsif collection.total_pages == 1
      "Displaying all #{collection.total_entries} #{models}"
    else
      "Displaying #{models} #{collection.offset + 1} " +
      "to #{collection.offset + collection.length} " +
      "of #{number_with_delimiter collection.total_entries} in total"
    end
  end
end

# Displaying contracts 1 - 35 of 4,825 in total