加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 百科 > 正文

如何将xml转为python中的字典

发布时间:2020-12-16 23:46:17 所属栏目:百科 来源:网络整理
导读:如何将xml转为python中的字典 import cElementTree as ElementTree class XmlListConfig(list): def __init__ (self,aList): for element in aList: if element: # treat like dict if len(element) == 1 or element[0].tag != element[1 ].tag: self.append

如何将xml转为python中的字典

import cElementTree as ElementTree

class XmlListConfig(list):
    def __init__(self,aList):
        for element in aList:
            if element:
                # treat like dict
                if len(element) == 1 or element[0].tag != element[1].tag:
                    self.append(XmlDictConfig(element))
                # treat like list
                elif element[0].tag == element[1].tag:
                    self.append(XmlListConfig(element))
            elif element.text:
                text = element.text.strip()
                if text:
                    self.append(text)


class XmlDictConfig(dict):
    ‘‘‘
    Example usage:

    >>> tree = ElementTree.parse(‘your_file.xml‘)
    >>> root = tree.getroot()
    >>> xmldict = XmlDictConfig(root)

    Or,if you want to use an XML string:

    >>> root = ElementTree.XML(xml_string)
    >>> xmldict = XmlDictConfig(root)

    And then use xmldict for what it is... a dict.
    ‘‘‘
    def __init__(self,parent_element):
        if parent_element.items():
            self.update(dict(parent_element.items()))
        for element in parent_element:
            if element:
                # treat like dict - we assume that if the first two tags
                # in a series are different,then they are all different.
                if len(element) == 1 or element[0].tag != element[1].tag:
                    aDict = XmlDictConfig(element)
                # treat like list - we assume that if the first two tags
                # in a series are the same,then the rest are the same.
                else:
                    # here,we put the list in dictionary; the key is the
                    # tag name the list elements all share in common,and
                    # the value is the list itself 
                    aDict = {element[0].tag: XmlListConfig(element)}
                # if the tag has attributes,add those to the dict
                if element.items():
                    aDict.update(dict(element.items()))
                self.update({element.tag: aDict})
            # this assumes that if you‘ve got an attribute in a tag,
            # you won‘t be having any text. This may or may not be a 
            # good idea -- time will tell. It works for the way we are
            # currently doing XML configuration files...
            elif element.items():
                self.update({element.tag: dict(element.items())})
            # finally,if there are no child tags and no attributes,extract
            # the text
            else:
                self.update({element.tag: element.text})

用法示例:

tree = ElementTree.parse(‘your_file.xml‘) root = tree.getroot() xmldict = XmlDictConfig(root) 

//或者,如果你想使用一个XML字符串:

root = ElementTree.XML(xml_string) xmldict = XmlDictConfig(root)学习了https://cloud.tencent.com/developer/ask/51220http://code.activestate.com/recipes/410469-xml-as-dictionary/

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读