如何在复杂的XML中将特定属性转换为元素

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<filter query="select" name="hello" description="world">
    <certification>WFA</certification>
    <uuid>fd5d9f15-f6d9-4e71-aaf4-024aaaa627f2</uuid>
    <parameters>
        <parameter type="STRING" name="name" label="name">
            <description>Some name</description>
        </parameter>
    </parameters>
    <returned-attributes>
        <returned-attribute>id</returned-attribute>
    </returned-attributes>
</filter>

我的愿望输出如下：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<filter name="hello" description="world">
    <certification>WFA</certification>
    <uuid>fd5d9f15-f6d9-4e71-aaf4-024aaaa627f2</uuid>
    <query>select<query/>
    <parameters>
        <parameter type="STRING" name="name" label="name">
            <description>Some name</description>
        </parameter>
    </parameters>
    <returned-attributes>
        <returned-attribute>id</returned-attribute>
    </returned-attributes>
</filter>

我使用以下XSLT：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:strip-space elements="*"/>
    <xsl:output indent="yes"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <!-- match the filter element -->
    <xsl:template match="filter">
        <xsl:choose>
            <xsl:when test="/filter/@query">
                <!-- output a filter element -->
                <xsl:element name="filter">

                    <!-- add the name attribute,using the source name attribute value -->
                    <xsl:attribute name="name">
                        <xsl:value-of select="@name"/>
                    </xsl:attribute>

                    <!-- add the description attribute (if found),using the source name attribute value -->
                    <xsl:choose>
                        <xsl:when test="/filter/@description">
                            <xsl:attribute name="description">
                                <xsl:value-of select="@description"/>
                            </xsl:attribute>
                        </xsl:when>
                    </xsl:choose>

                    <!-- add the query as child element,using the source query attribute value -->
                    <xsl:element name="query">
                        <xsl:value-of select="@query"/>
                    </xsl:element>

                    <!-- add all common elements -->
                    <xsl:element name="certification">
                        <xsl:value-of select="certification"/>
                    </xsl:element>
                    <xsl:element name="uuid">
                        <xsl:value-of select="uuid"/>
                    </xsl:element>

                    <!-- copy parameters -->
                    <xsl:copy>
                        <xsl:apply-templates select="/filter/parameters"/>
                    </xsl:copy>

                    <!-- copy attributes -->
                    <xsl:copy>
                        <xsl:apply-templates select="/filter/returned-attributes"/>
                    </xsl:copy>
                </xsl:element>
            </xsl:when>
            <xsl:otherwise>
                <xsl:copy>
                    <xsl:apply-templates select="@*|node()"/>
                </xsl:copy>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>

</xsl:stylesheet>

转型有效,但在我看来很复杂.
注意,我使用if / else逻辑,因为我的输入可以包含“old”(未转换)和
“新”(转换)的XML文件.

请指教.提前致谢.