将JSONObject转换为Java对象
发布时间:2020-12-16 19:51:57 所属栏目:百科 来源:网络整理
导读:我对服务进行了休息调用,并将响应存储在 JSONObject中.但是,我试图将其转换为类对象并获得错误.这是我的代码: RestOperations operations = /*initalize*/;String body = /*build request body*/;String resourceResponse = operations.postForObject(/* ur
我对服务进行了休息调用,并将响应存储在
JSONObject中.但是,我试图将其转换为类对象并获得错误.这是我的代码:
RestOperations operations = /*initalize*/; String body = /*build request body*/; String resourceResponse = operations.postForObject(/* url */,body,String.class); JSONObject jsonResponse = new JSONObject(resourceResponse); UserIdentifier userIdentifier = (UserIdentifier) jsonResponse.get("userIdentifier"); 这是响应的样子: { "userIdentifier": { "uid": "ee63a52cda7bf411dd8603ac196951aa77","code": "63a5297e7bf411dd8603ac196951aa77","retailId": "860658787","pointOfEntry": "RETAIL" },"resultCode": true } 这是UserIdentifier类的样子: public class UserIdentifier { private String uid; private String code; private String retailId; public UserIdentifier() { } public UserIdentifier(String uid,String code,String retailId) { this.uid = uid; this.code = code; this.retailId = retailId; } public String getuid() { return uid; } public void setuid(String uid) { this.uid = uid; } public String getcode() { return code; } public void setcode(String code) { this.code = code; } public String getretailId() { return retailId; } public void setretailId(String retailId) { this.retailId = retailId; } } 但我得到错误: java.lang.ClassCastException: org.json.JSONObject cannot be cast to app.identity.UserIdentifier 我究竟做错了什么? 编辑1:这是尝试从答案中使用gson: Gson gson = new GsonBuilder().create(); String body = /*build request body*/; String resourceResponse = operations.postForObject(/* url */,String.class); JSONObject jsonResponse = new JSONObject(resourceResponse); UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getString("userIdentifier"),UserIdentifier.class); 但我得到错误: org.json.JSONException: JSONObject["userIdentifier"] not a string. at org.json.JSONObject.getString(JSONObject.java:658) ~[json-20140107.jar:na]
你可能需要使用gson
class Name{ String resultCode; UserIdentifier useridentifier; //getters } Gson gson=new Gson(); Name name=gson.fromJson(jsonString,Name.class); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |