fastjson 第三方jar和java各种数据对象相互转化
发布时间:2020-12-16 19:16:33 所属栏目:百科 来源:网络整理
导读:package com.saic.grape.utils; import java.util.Map; import com.meidusa.fastjson.JSON; import com.meidusa.fastjson.JSONObject; import com.saic.grape.entity.KeyValue; import com.saic.grape.entity.UserLogin; /** * Copyright (C),2014-4-22, * @
package com.saic.grape.utils;
import java.util.Map; import com.meidusa.fastjson.JSON; import com.meidusa.fastjson.JSONObject; import com.saic.grape.entity.KeyValue; import com.saic.grape.entity.UserLogin; /** * Copyright (C),2014-4-22, * @version 1.0 * @date 2014-4-22 javaBean转化为字符串公共类 * @author SHENBO */ public class FastJsonUtil { /** * 将javabean转化为序列化的json字符串 * @param keyvalue * @return */ public static Object beanToJson(KeyValue keyvalue) { String textJson = com.meidusa.fastjson.JSON.toJSONString(keyvalue); Object objectJson = JSON.parse(textJson); return objectJson; } * 将string转化为序列化的json字符串 public static Object textToJson(String text) { Object objectJson = JSON.parse(text); * json字符串转化为map * @param s public static Map stringToCollect(String s) { Map m = (Map) JSONObject.parSEObject(s); return m; * 将map转化为string * @param m public static String collectToString(Map m) { String s = JSONObject.toJSONString(m); return s; * json字符串转化为javabean public static UserLogin jsonToJavaBean(String s) { UserLogin userLogin = JSONObject.parSEObject(s,UserLogin.class); return userLogin; public static void main(String[] args) { String str = "{"appCode":"Grape","appVersion":"1.0","deviceId":"236fa43ed352cc235","sourceId":"1c1c1c","userAccount":"13812345678","userToken":"123456789"}"; Map ma = FastJsonUtil.stringToCollect(str); String ss = "{"velModelId":10000,"velModelName":"奥迪"}"; //LoginResultVelModel vd = FastJsonUtil.jsonToJavaBean(ss); //System.out.println(vd.getVelModelName()); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |