c – 使用auto作为参数是否有负面影响？

#include <iostream>
#include <functional>

class Functor
{
public:
    void operator()()
    {
        std::cout << "Functor operator called." << std::endl;
    }
};

void Function()
{
    std::cout << "Function called." << std::endl;
}

void Call( auto & fp )
{
    static int i;
    std::cout << "Unified calling..." << &i << std::endl;
    fp();
}

int main( int argc,char ** argv )
{
    Functor functor;
    std::function< void() > function = Function;

    std::cout << "Begin testing..." << std::endl;
    Call( functor );
    Call( function );
    std::cout << "End testing." << std::endl;

    return 0;
}


Compiled with: g++ main.cpp -std=c++14
output:
Begin testing...
Unified calling...0x100402080
Functor operator called.
Unified calling...0x100402090
Function called.
End testing.

从静态地址我可以看出,这产生了两个不同的功能,所以在我看来,它就像一个模板简写,一种类型.我的直觉是,要维护的一个函数优于多个函数,但是,除了注意非共享的静态变量之外,我是否遗漏了一些可能使这个选项变得糟糕而不是多个函数定义的东西？