c – 如何传递缺少参数的函数？

有关详细信息,请查看this answer.

using namespace std::placeholders;  // for _1,_2,_3...
// Fix first argument as 10
auto fce_third_arg_is_5 = bind(fce,5,_3);
/* foo(function); */
foo(fce_third_arg_is_5);

在c中,您可以通过编写新的转换器功能来完成此操作

/* Can be used only in global scope */
#define GEN_FUNC(X) double templated_fn_##X(double t,double y) {return fce(t,y,X);}

GEN_FUNC(5);
...
/* foo(function); */
foo(templated_fn_5);

或通用解决方案：

static int a_val_g;

static double wrapper(double t,double y)
{
  return fce(t,a_val_g);
}

function make_func(int a) {
  /* Warning: Not thread safe. Subsequent call will invalidate previously returned function */
  /* fn(make_func(i),make_func(42); is bad */
  /* Using make_func in a multithreaded application is unsafe unless synchronized properly */
  a_val_g = a;
  return wrapper;
}
...
/* foo(function); */
foo(make_func(5));