在C中乘以两个矩阵
发布时间:2020-12-16 09:53:46 所属栏目:百科 来源:网络整理
导读:我正在编写一个程序,它接受两个不同矩阵的元素,然后它将它们相乘,接下来它将它们保存在一个多维数组中. 但它只适用于方阵. (Visual Studio 2013没有错误.) 如果你帮我编辑这段代码以便繁殖各种矩阵,我会很高兴的. int a,b,c,d; int Mat1[10][10]; int Mat2[1
我正在编写一个程序,它接受两个不同矩阵的元素,然后它将它们相乘,接下来它将它们保存在一个多维数组中.
但它只适用于方阵. (Visual Studio 2013没有错误.) 如果你帮我编辑这段代码以便繁殖各种矩阵,我会很高兴的. int a,b,c,d; int Mat1[10][10]; int Mat2[10][10]; int Mat3[10][10]; Back1: cout << endl << "Enter the number of rows in Matrix 1 : "; cin >> a; cout << endl << "Enter the number of columns in Matrix 1 : "; cin >> b; cout << endl << "Enter the number of rows in Matrix 2 : "; cin >> c; cout << endl << "Enter the number of column in Matrix 2 : "; cin >> d; if (b != c) { cout << endl << "******************************************" << "nThis type of Matrix can't be multiplied . " << endl; goto Back1; } for (int i = 0; i < a; i++) { for (int j = 0; j < b; j++) { cout << endl << "(MAT 1 ) nnEnter the Element of row " << i + 1 << " column " << j + 1 << " : "; cin >> Mat1[i][j]; } } for (int i = 0; i < c; i++) { for (int j = 0; j < d; j++) { cout << endl << "(MAT 2 ) nnEnter the Element of row " << i + 1 << " column " << j + 1 << " : "; cin >> Mat2[i][j]; } } for (int i = 0; i < a; i++) { for (int j = 0; j < d; j++) { Mat3[i][j] = Mat1[i][j] * Mat1[i][j]; } } for (int i = 0; i < a; i++) { for (int j = 0; j < d; j++) { cout << setw(4) << Mat3[i][j] << setw(4); } cout << endl; } } 解决方法
你的矩阵乘法代码是错误的.代替:
for (int i = 0; i < a; i++) { for (int j = 0; j < d; j++) { Mat3[i][j] = Mat1[i][j] * Mat1[i][j]; } } 你需要: for (int i = 0; i < a; i++) { for (int j = 0; j < d; j++) { Mat3[i][j] = 0; for (int k = 0; k < c; k++) { Mat3[i][j] += Mat1[i][k] * Mat2[k][j]; } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |