虽然声明不起作用C.
发布时间:2020-12-16 09:45:51 所属栏目:百科 来源:网络整理
导读:我正在学习C,而我正在尝试制作一个基本的计算器,但是在使用while语句时遇到了一些麻烦.我尝试过多种方式,但它从不重复,只需完成脚本. 有任何想法吗? //// main.c// Calculator//// Created by Austen Patterson on 2013-06-27.// Copyright (c) 2013 Austen
我正在学习C,而我正在尝试制作一个基本的计算器,但是在使用while语句时遇到了一些麻烦.我尝试过多种方式,但它从不重复,只需完成脚本.
有任何想法吗? // // main.c // Calculator // // Created by Austen Patterson on 2013-06-27. // Copyright (c) 2013 Austen Patterson. All rights reserved. // #include <stdio.h> #include <stdbool.h> int main() { int number[100]; int operator = '0'; int doAgainAnswer = '0'; bool doAgain; do{ printf("Please enter your first number:"); scanf("%d",&number[1]); printf("nYou entered %d as your first number. Please enter your second: ",number[1]); scanf("%d",&number[2]); printf("nYou entered %d as your second number.",number[2]); printf("nYour numbers are now %d and %d",number[1],number[2]); printf("nNow enter your operator.n1 for additionn2 for subractionn3 for multiplicationn4 for division.n"); scanf("%d",&operator); if(operator == 1){ int finished = number[1] + number[2]; printf("nn%d + %d is: %d",number[2],finished); } if(operator == 2){ int finished = number[1] - number[2]; printf("nn%d - %d is: %d",finished); } if(operator == 3){ int finished = number[1] * number[2]; printf("nn%d * %d is: %d",finished); } if(operator == 4){ int finished = number[1] / number[2]; printf("nn%d / %d is: %d",finished); } printf("nWant to continue?n 1 for Yesn 2 for NonAnswer: "); scanf("%d",&doAgainAnswer); if(doAgainAnswer == 1) { doAgain = '1'; } else { doAgain = '0'; } }while(doAgain == '1'); } 解决方法
编辑过的代码
#include <stdio.h> #include <stdbool.h> int main() { int number[100]; int operator = '0'; int doAgainAnswer = 0;//edited int doAgain=0;//edited do{ printf("Please enter your first number:"); scanf("%d",&doAgainAnswer); if(doAgainAnswer == 1) { doAgain = 1;//edited } else { doAgain = 0;//edited } }while(doAgain == 1);//edited return 0;//edited } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |