编译简单的hello world ZeroMQ C的例子,编译标志？

发布时间：2020-12-16 07:52:28 所属栏目：百科来源：网络整理

导读：尝试从zeromq教程编译示例hello_world.c： http://zguide.zeromq.org/page:all#Ask-and-Ye-Shall-Receive 相当肯定我有一切安装在OSX山狮. clang -Wall hwserver.c -o hwserver 给我一个错误： Undefined symbols for architecture x86_64: "_zmq_bind",refe

尝试从zeromq教程编译示例hello_world.c：
http://zguide.zeromq.org/page:all#Ask-and-Ye-Shall-Receive
相当肯定我有一切安装在OSX山狮.

clang -Wall hwserver.c -o hwserver

给我一个错误：

Undefined symbols for architecture x86_64:  
"_zmq_bind",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_ctx_new",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_close",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_data",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_init",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_init_size",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_recv",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_msg_send",referenced from:  
  _main in hwserver-OgrEe6.o  
"_zmq_socket",referenced from:  
  _main in hwserver-OgrEe6.o  
ld: symbol(s) not found for architecture x86_64  
clang: error: linker command failed with exit code 1 (use -v to see invocation)

我不是最有经验的C.不知道如果我确定添加一个编译器标志为zmq dylib或头或我的$PATH关闭.

在/usr/local / lib中：

libzmq.3.dylib
libzmq.a
libzmq.dylib
libzmq.la

并在/usr/local / include：

zmq.h
zmq_utils.h

和echo $PATH：

/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/local/lib/:/usr/local/include/

解决方法

您在问题中列出了ZeroMQ库,但实际上并没有链接到它们.将命令行更改为：

clang -Wall hwserver.c -o hwserver -L/usr/local/lib -lzmq

说明额外的论据：

> -L /usr/local / lib告诉链接器向库搜索路径添加路径(/usr/local / lib).
> -lzmq告诉库与zmq库链接.

$PATH环境变量与此无关,它只是告诉shell在哪里查找命令.

（编辑：李大同）

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