c：通过多级继承从模板子类调用基类的模板方法

template <class PType>
class A
{
public:
    template <class ChildClass>
    void Func( void )
    {
        std::cout << "Called A<PType>::Func<ChildClass>" << std::endl;
    }
};

template <class PType>
class B : public A<PType>
{
};

template <class PType>
class C : public A<PType>
{
};

class D : public B<int>,public C<int>
{
public:
    D()
    {
        static_cast<B<int>*>( this )->A<int>::Func<D>();
        static_cast<C<int>*>( this )->A<int>::Func<D>();
    }
};

这按预期工作,D在初始化时使用子类的模板参数调用B :: A :: Func和C :: A :: Func.但是,当D是模板类时,这似乎不起作用.

template <class PType>
class D2 : public B<PType>,public C<PType>
{
public:
    D2()
    {
        //expected primary-expression before ‘>’ token
        //expected primary-expression before ‘)’ token
        static_cast<B<PType>*>( this )->A<PType>::Func< D2<PType> >();
        static_cast<C<PType>*>( this )->A<PType>::Func< D2<PType> >();
    }
};

问题似乎是模板参数D2到Func,但无法解决这个问题.