SAX简单解析XML
发布时间:2020-12-16 06:18:21 所属栏目:百科 来源:网络整理
导读:package com.zkn.xmlparse.text;import java.io.File;import java.util.Iterator;import org.dom4j.Attribute;import org.dom4j.Document;import org.dom4j.Element;import org.dom4j.io.SAXReader;/** * pTitle: /p * * pDescription: /p * * @since:2015-
package com.zkn.xmlparse.text; import java.io.File; import java.util.Iterator; import org.dom4j.Attribute; import org.dom4j.Document; import org.dom4j.Element; import org.dom4j.io.SAXReader; /** * <p>Title: </p> * * <p>Description: </p> * * @since:2015-6-3 下午12:40:10 * */ public class XMLParseTest02 { public static void main(String[] args) throws Exception { SAXReader reader = new SAXReader(); Document document = reader.read(new File("src/mapping.xml")); Element element = document.getRootElement(); getElement(element); } public static void getElement(Element element) { /** * 得到tag名字 */ String elements = element.getName(); Iterator<?> ite = element.attributes().iterator(); String attrName = ""; while(ite.hasNext()) { Attribute attr = (Attribute)ite.next(); attrName += attr.getName() + "="+attr.getValue()+" "; } System.out.println("元素名字:"+elements+" 属性:"+attrName); Iterator<?> it = element.elements().iterator(); while(it.hasNext()){ Element ele = (Element)it.next(); //递归调用 getElement(ele); } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |