c – 使用initializer_list初始化数组?
发布时间:2020-12-16 05:52:26 所属栏目:百科 来源:网络整理
导读:参见英文答案 How do I initialize a member array with an initializer_list?5个 这是否可能? #include array#include initializer_liststruct A{ A ( std::initializer_list int l ) : m_a ( l ) { } std::arrayint,2 m_a;};int main(){ A a{ 1,2 };} 但
参见英文答案 >
How do I initialize a member array with an initializer_list?5个
这是否可能? #include <array> #include <initializer_list> struct A { A ( std::initializer_list< int > l ) : m_a ( l ) { } std::array<int,2> m_a; }; int main() { A a{ 1,2 }; } 但是这会导致这个错误: t.cpp: In constructor ‘A::A(std::initializer_list<int>)’: t.cpp:7:19: error: no matching function for call to ‘std::array<int,2ul>::array(std::initializer_list<int>&)’ : m_a ( l ) ^ t.cpp:7:19: note: candidates are: In file included from t.cpp:1:0: /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: std::array<int,2ul>::array() struct array ^ /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: candidate expects 0 arguments,1 provided /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int,2ul>::array(const std::array<int,2ul>&) /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘const std::array<int,2ul>&’ /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int,2ul>::array(std::array<int,2ul>&&) /usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘std::array<int,2ul>&&’ 解决方法
不是这种情况.您可以使用列表初始化程序初始化数组
std::array<int,2> a{1,2}; 但是您不能使用initializer_list初始化数组,因为数组只是一个只有默认和复制构造函数的聚合类型. 您可以将阵列留空,然后将initializer_list的内容复制到其中. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |