C++计算每个字符出现的次数
发布时间:2020-12-16 05:25:42 所属栏目:百科 来源:网络整理
导读:本文实例为大家分享了C++计算每个字符出现的次数的实现代码,供大家参考,具体内容如下 #include iostream//#include cstdlib#include ctimeusing namespace std; const int NUMBER_OF_LETTERS = 26;const int NUMBER_OF_RANDOM_LETTERS = 100;void createAr
本文实例为大家分享了C++计算每个字符出现的次数的实现代码,供大家参考,具体内容如下 #include <iostream> //#include <cstdlib> #include <ctime> using namespace std; const int NUMBER_OF_LETTERS = 26; const int NUMBER_OF_RANDOM_LETTERS = 100; void createArray(char []); void displayArray(const char []); void countLetters(const char [],int []); void displayCounts(const int []); int main() { char chars[NUMBER_OF_RANDOM_LETTERS]; createArray(chars); cout << "The lowercase letters are:" << endl; displayArray(chars); int counts[NUMBER_OF_LETTERS]; countLetters(chars,counts); cout << "nThe occurrences of each letter are:" << endl; displayCounts(counts); return 0; } void createArray(char chars[]) { srand((unsigned int)time(0)); for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { chars[i] = static_cast<char>('a' + rand() % ('z' - 'a' + 1)); } } void displayArray(const char chars[]) { for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { if ((i + 1) % 20 == 0) cout << chars[i] << " " << endl; else cout << chars[i] << " "; } } void countLetters(const char chars[],int counts[]) { for (int i = 0; i < NUMBER_OF_LETTERS; i++) counts[i] = 0; for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) counts[chars[i] - 'a']++; //经典 } void displayCounts(const int counts[]) { for (int i = 0; i < NUMBER_OF_LETTERS; i++) { if ((i + 1) % 10 == 0) cout << counts[i] << " " << static_cast<char>(i + 'a') << endl; else cout << counts[i] << " " << static_cast<char>(i + 'a') << " "; } cout << endl; } 以上就是本文的全部内容,希望对大家的学习有所帮助。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |