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c# – 单元测试上载文件的Web API端点

发布时间:2020-12-16 01:27:16 所属栏目:百科 来源:网络整理
导读:我有一个web api终点,我想进行单元测试.我有一个自定义的SwaggerUploadFile属性,允许在swagger页面上的文件上传按钮.但是对于单元测试,我无法弄清楚如何传入文件. 对于单元测试,我使用:Xunit,Moq和Fluent Assertions 下面是我的控制器与端点: public class
我有一个web api终点,我想进行单元测试.我有一个自定义的SwaggerUploadFile属性,允许在swagger页面上的文件上传按钮.但是对于单元测试,我无法弄清楚如何传入文件.

对于单元测试,我使用:Xunit,Moq和Fluent Assertions

下面是我的控制器与端点:

public class MyAppController : ApiController
{
    private readonly IMyApp _myApp;

    public MyAppController(IMyApp myApp)
    {
         if (myApp == null) throw new ArgumentNullException(nameof(myApp));
         _myApp = myApp;
    }

    [HttpPost]
    [ResponseType(typeof(string))]
    [Route("api/myApp/UploadFile")]
    [SwaggerUploadFile("myFile","Upload a .zip format file",Required = true,Type = "file")]
    public async Task<IHttpActionResult> UploadFile()
    {
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }

        var provider = await Request.Content.ReadAsMultipartAsync();
        var bytes = await provider.Contents.First().ReadAsByteArrayAsync();
        try
        {
           var retVal = _myApp.CheckAndSaveByteStreamAsync(bytes).Result;
           if(retVal)
            {
                return
                    ResponseMessage(
                        new HttpResponseMessage(HttpStatusCode.OK)
                        {
                            Content = new StringContent(JsonConvert.SerializeObject(
                                new WebApiResponse
                                {
                                    Message = "File has been saved"
                                }),Encoding.UTF8,"application/json")
                        });
            }             
            return ResponseMessage(
                new HttpResponseMessage(HttpStatusCode.BadRequest)
                {
                    Content = new StringContent(JsonConvert.SerializeObject(
                        new WebApiResponse
                        {
                            Message = "The file could not be saved"
                        }),"application/json")
                });
        }
        catch (Exception e)
        {
            //log error
            return BadRequest("Oops...something went wrong");
        }
    }    
}

我到目前为止的单元测试:

[Fact]
    [Trait("Category","MyAppController")]
    public void UploadFileTestWorks()
    {
        //Arrange

        _myApp.Setup(x => x.CheckAndSaveByteStreamAsync(It.IsAny<byte[]>())).ReturnsAsync(() => true);
        var expected = JsonConvert.SerializeObject(
            new WebApiResponse
            {
                Message = "The file has been saved"
            });

        var _sut = new MyAppController(_myApp.Object);


        //Act
        var retVal = _sut.UploadFile();
        var content = (ResponseMessageResult)retVal.Result;
        var contentResult = content.Response.Content.ReadAsStringAsync().Result;
        //Assert
        contentResult.Should().Be(expected); 
    }

如果(!Request.Content.IsMimeMultipartContent())我们得到NullReferenceException> “{“你调用的对象是空的.”}”

最佳答案已实施:

创建了一个界面:

public interface IApiRequestProvider
    {
        Task<MultipartMemoryStreamProvider> ReadAsMultiPartAsync();

        bool IsMimeMultiPartContent();
    }

然后是一个实现:

public class ApiRequestProvider : ApiController,IApiRequestProvider
    {       
        public Task<MultipartMemoryStreamProvider> ReadAsMultiPartAsync()
        {
            return Request.Content.ReadAsMultipartAsync();
        }
        public bool IsMimeMultiPartContent()
        {
            return Request.Content.IsMimeMultipartContent();
        }
    }

现在我的控制器使用构造函数注入来获取RequestProvider:

private readonly IMyApp _myApp;
 private readonly IApiRequestProvider _apiRequestProvider;

 public MyAppController(IMyApp myApp,IApiRequestProvider apiRequestProvider)
        {
             if (myApp == null) throw new ArgumentNullException(nameof(myApp));
             _myApp = myApp;

             if (apiRequestProvider== null) throw new ArgumentNullException(nameof(apiRequestProvider));
             _apiRequestProvider= apiRequestProvider;
        }

方法的新实现:

[HttpPost]
        [ResponseType(typeof(string))]
        [Route("api/myApp/UploadFile")]
        [SwaggerUploadFile("myFile",Type = "file")]
        public async Task<IHttpActionResult> UploadFile()
        {
            if (!_apiRequestProvider.IsMimeMultiPartContent())
            {
                throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
            }

            var provider = await _apiRequestProvider.ReadAsMultiPartAsync();
            var bytes = await provider.Contents.First().ReadAsByteArrayAsync();
            try
            {
               var retVal = _myApp.CheckAndSaveByteStreamAsync(bytes).Result;
               if(retVal)
                {
                    return
                        ResponseMessage(
                            new HttpResponseMessage(HttpStatusCode.OK)


             {
                            Content = new StringContent(JsonConvert.SerializeObject(
                                new WebApiResponse
                                {
                                    Message = "File has been saved"
                                }),"application/json")
                });
        }
        catch (Exception e)
        {
            //log error
            return BadRequest("Oops...something went wrong");
        }
    }    
}

我的单元测试嘲笑ApiController请求:

[Fact]
    [Trait("Category","MyAppController")]
    public void UploadFileTestWorks()
    {
        //Arrange
        _apiRequestProvider = new Mock<IApiRequestProvider>();
        _myApp = new Mock<IMyApp>();
         MultipartMemoryStreamProvider fakeStream = new MultipartMemoryStreamProvider();
        fakeStream.Contents.Add(CreateFakeMultiPartFormData());
        _apiRequestProvider.Setup(x => x.IsMimeMultiPartContent()).Returns(true);
        _apiRequestProvider.Setup(x => x.ReadAsMultiPartAsync()).ReturnsAsync(()=>fakeStream);
        _myApp.Setup(x => x.CheckAndSaveByteStreamAsync(It.IsAny<byte[]>())).ReturnsAsync(() => true);
        var expected = JsonConvert.SerializeObject(
            new WebApiResponse
            {
                Message = "The file has been saved"
            });

        var _sut = new MyAppController(_myApp.Object,_apiRequestProvider.Object);

        //Act
        var retVal = _sut.UploadFile();
        var content = (ResponseMessageResult)retVal.Result;
        var contentResult = content.Response.Content.ReadAsStringAsync().Result;
        //Assert
        contentResult.Should().Be(expected); 
    }

感谢@Badulake的想法

解决方法

你应该在方法的逻辑中做一个更好的分离.
重构您的方法,因此它不依赖于与您的Web框架相关的任何类,在本例中是Request类.您的上传代码无需了解任何相关信息.
作为提示:

var provider = await Request.Content.ReadAsMultipartAsync();

可以转换为:

var provider = IProviderExtracter.Extract();

public interface IProviderExtracter
{
    Task<provider> Extract();
}

public class RequestProviderExtracter:IProviderExtracter
{
    public Task<provider> Extract()
    { 
      return Request.Content.ReadAsMultipartAsync();
    }
}

在您的测试中,您可以轻松地模拟IProviderExtracter,并专注于执行代码的每个部分.

我们的想法是获得最多的解耦代码,因此您的担忧只集中在模拟您开发的类,而不是框架强制您使用的类.

(编辑:李大同)

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