C#程序只允许运行一个实例的解决方案
发布时间:2020-12-16 01:25:41 所属栏目:百科 来源:网络整理
导读:最近在做winform的程序中,需要只能打开一个程序,如果已经存在,则激活该程序的窗口,并显示在最前端。在网上google了一哈,找到了很多的解决方案。这里我整理了3种方案,并经过了测试,现和朋友们分享: 一、使用用互斥量(System.Threading.Mutex) ?同步基
最近在做winform的程序中,需要只能打开一个程序,如果已经存在,则激活该程序的窗口,并显示在最前端。在网上google了一哈,找到了很多的解决方案。这里我整理了3种方案,并经过了测试,现和朋友们分享: 一、使用用互斥量(System.Threading.Mutex) ?同步基元,它只向一个线程授予对共享资源的独占访问权。在程序启动时候,请求一个互斥体,如果能获取对指定互斥的访问权,就职运行一个实例。
?bool?createNew;
????????????using?(System.Threading.Mutex?mutex?=?new?System.Threading.Mutex(true,?Application.ProductName,?out?createNew)) ????????????{ ????????????????if?(createNew) ????????????????{ ????????????????????Application.Run(new?Form1()); ????????????????} ????????????????else ????????????????{ ????????????????????MessageBox.Show("应用程序已经在运行中...")
????????????????????System.Threading.Thread.Sleep(1000);
????????????????????System.Environment.Exit(1); ????????????????} ????????????} ? ? 二、使用进程名 ?
???Process[]?processes?=?System.Diagnostics.Process.GetProcessesByName(Application.CompanyName);
????????????if?(processes.Length?>?1) ????????????{ ????????????????MessageBox.Show("应用程序已经在运行中。。"); ????????????????Thread.Sleep(1000); ????????????????System.Environment.Exit(1); ????????????} ????????????else ????????????{ ????????????????Application.Run(new?Form1()); ????????????} ? ? 三、调用Win32 API,并激活并程序的窗口,显示在最前端 ?
??///?该函数设置由不同线程产生的窗口的显示状态
????????///?</summary> ????????///?<param?name="hWnd">窗口句柄</param> ????????///?<param?name="cmdShow">指定窗口如何显示。查看允许值列表,请查阅ShowWlndow函数的说明部分</param> ????????///?<returns>如果函数原来可见,返回值为非零;如果函数原来被隐藏,返回值为零</returns> ????????[DllImport("User32.dll")] ????????private?static?extern?bool?ShowWindowAsync(IntPtr?hWnd,?int?cmdShow); ????????///?<summary> ????????///??该函数将创建指定窗口的线程设置到前台,并且激活该窗口。键盘输入转向该窗口,并为用户改各种可视的记号。 ????????///??系统给创建前台窗口的线程分配的权限稍高于其他线程。? ????????///?</summary> ????????///?<param?name="hWnd">将被激活并被调入前台的窗口句柄</param> ????????///?<returns>如果窗口设入了前台,返回值为非零;如果窗口未被设入前台,返回值为零</returns> ????????[DllImport("User32.dll")] ????????private?static?extern?bool?SetForegroundWindow(IntPtr?hWnd); ? ?
??private?const?int?SW_SHOWNOMAL?=?1;
????????private?static?void?HandleRunningInstance(Process?instance) ????????{ ????????????ShowWindowAsync(instance.MainWindowHandle,?SW_SHOWNOMAL);//显示 ????????????SetForegroundWindow(instance.MainWindowHandle);//当到最前端 ????????} ????????private?static?Process?RuningInstance() ????????{ ????????????Process?currentProcess?=?Process.GetCurrentProcess(); ????????????Process[]?Processes?=?Process.GetProcessesByName(currentProcess.ProcessName); ????????????foreach?(Process?process?in?Processes) ????????????{ ????????????????if?(process.Id?!=?currentProcess.Id) ????????????????{ ????????????????????if?(Assembly.GetExecutingAssembly().Location.Replace("/",?"")?==?currentProcess.MainModule.FileName) ????????????????????{ ????????????????????????return?process; ????????????????????} ????????????????} ????????????} ????????????return?null; ????????} ?
??Process?process?=?RuningInstance();
????????????if?(process?==?null) ????????????{ ????????????????Application.Run(new?Form1()); ????????????} ????????????else ????????????{ ????????????????MessageBox.Show("应用程序已经在运行中。。。");
??????????????? HandleRunningInstance(process);
????????????????//System.Threading.Thread.Sleep(1000); ????????????????//System.Environment.Exit(1); ????????????} (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |