c# – 将KeyValue对分组到Dictionary

发布时间：2020-12-16 00:14:37 所属栏目：百科来源：网络整理

导读：我有以下代码： using System.Collections.Generic;public class Test{ static void Main() { var items = new ListKeyValuePairint,User { new KeyValuePairint,User(1,new User {FirstName = "Name1"}),new KeyValuePairint,new User {FirstName = "Name2"

我有以下代码：

using System.Collections.Generic;


public class Test
{
    static void Main()
    {

        var items = new List<KeyValuePair<int,User>>
                        {
                            new KeyValuePair<int,User>(1,new User {FirstName = "Name1"}),new KeyValuePair<int,new User {FirstName = "Name2"}),User>(2,new User {FirstName = "Name3"}),new User {FirstName = "Name4"})
                        };

    }
}
public class User
{
    public string FirstName { get; set; }
}

如上所示,同一个密钥有多个用户.现在我想将它们分组并将列表对象转换为字典,其中Key将是相同的(1,2如上所示),但值将是集合.如下所示：

var outputNeed = new Dictionary<int,Collection<User>>();
        //Output:
        //1,Collection<User>
        //2,Collection<User>

即他们现在分组.

我怎样才能做到这一点？

解决方法

我建议你改用 Lookup<TKey,TElement>.此数据结构专门用作从键到值集合的映射.

//uses Enumerable.ToLookup: the Id is the key,and the User object the value
var outputNeeded = items.ToLookup(kvp => kvp.Key,kvp => kvp.Value);

当然,如果你确实需要字典(也许允许变通),你可以这样做：

var outputNeeded = new Dictionary<int,Collection<User>>();

foreach(var kvp in list)
{
   Collection<User> userBucketForId;

   if(!outputNeeded.TryGetValue(kvp.Key,out userBucketForId)) 
   {
       // bucket doesn't exist,create a new bucket for the Id,containing the user
       outputNeeded.Add(kvp.Key,new Collection<User> { kvp.Value });
   }
   else 
   {   // bucket already exists,append user to it.
       userBucketForId.Add(kvp.Value);
   }
}

另一方面,除非你打算将它子类化,否则theCollection< T>类并不是那么有用.您确定不仅仅需要aList< User>？

（编辑：李大同）

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