c# – 如何从web api获取响应消息？

发布时间：2020-12-15 22:19:04 所属栏目：百科来源：网络整理

导读：我有以下Web控制器： Liststring output = new Liststring();output.Add("line1");output.Add("line2");output.Add("line3");output.Add("line4");using (var memorystream = new MemoryStream()){ using (var archive = new ZipArchive(memorystream,ZipArc

我有以下Web控制器：

List<string> output = new List<string>();
output.Add("line1");
output.Add("line2");
output.Add("line3");
output.Add("line4");

using (var memorystream = new MemoryStream())
{
    using (var archive = new ZipArchive(memorystream,ZipArchiveMode.Create,true))
    {
        var fileInArchive = archive.CreateEntry("entry1");
        using (var entryStream = fileInArchive.Open())
        using (var streamWriter = new StreamWriter(entryStream))
        {
            output.ForEach(streamWriter.WriteLine);
        }
    }

    memorystream.Seek(0,SeekOrigin.Begin);

    var result = new HttpResponseMessage(HttpStatusCode.OK)
    {
        Content = new ByteArrayContent(memorystream.GetBuffer())
    };
    result.Content.Headers.ContentDisposition = 
            new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment")
    {
        FileName = "test.zip"
    };
    result.Content.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
    return result;
}

在接收端,我有一个c#web表单,以这种方式访问??控制器：

var responsebody = response.Content.ReadAsByteArrayAsync().Result;

string filename = "test.zip";

HttpContext.Current.Response.Clear();
HttpContext.Current.Response.ClearHeaders();
HttpContext.Current.Response.AppendHeader(
            "content-disposition",string.Format("attachment; filename={0}",filename));
HttpContext.Current.Response.ContentType = "application/zip";
HttpContext.Current.Response.BinaryWrite(responsebody.ToArray());

但我只是在reponsebody var中得到一个字节数组.我如何将其转换回原始类型,这是一个ziparchive,或只是另一个二进制文件,使其更通用？

解决方法

How can I convert this back to the original type,which is a
ZipArchive?

您发送了byte []作为响应.这意味着,在接收端,你必须完全扭转相同的过程.意思是,你把字节数组放到ZipArchive中,然后开始阅读：

var bytes = await response.Content.ReadAsByteArrayAsync();

using (var zippedBytesStream = new MemoryStream(bytes))
using (var archive = new ZipArchive(zippedBytesStream,ZipArchiveMode.Read,true))
{
    foreach (ZipEntry entry in archive.Entries)
    {
       // Do stuff with entry.
    }
}

（编辑：李大同）

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