c# – 为structure-map 3中的DecorateAllWith()方法定义过滤器
发布时间:2020-12-15 22:15:38 所属栏目:百科 来源:网络整理
导读:我使用以下语句来装饰我的所有ICommandHandlers与Decorator1: ObjectFactory.Configure(x ={ x.For(typeof(ICommandHandler)).DecorateAllWith(typeof(Decorator1));}); 但是因为Decorator1实现ICommandHandlers,Decorator1 class也装饰自己. 因此,问题是当
我使用以下语句来装饰我的所有ICommandHandlers<>与Decorator1<>:
ObjectFactory.Configure(x => { x.For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>)); }); 但是因为Decorator1<>实现ICommandHandlers<>,Decorator1<> class也装饰自己. 因此,问题是当我注册所有ICommandHandler<>时,Decorator1无意中注册. 解决方法ObjectFactory 已经过时了.
您可以排除Decorator1<>从注册为香草ICommandHandler<>使用这样的代码: var container = new Container(config => { config.Scan(scanner => { scanner.AssemblyContainingType(typeof(ICommandHandler<>)); scanner.Exclude(t => t == typeof(Decorator1<>)); scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>)); }); config.For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>)); }); UPDATE 对于多个模块,您可以使用The Registry DSL组成应用程序的一部分 using StructureMap; using StructureMap.Configuration.DSL; public class CommandHandlerRegistry : Registry { public CommandHandlerRegistry() { Scan(scanner => { scanner.AssemblyContainingType(typeof(ICommandHandler<>)); scanner.Exclude(t => t == typeof(Decorator1<>)); scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>)); }); For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>)); } } 只有组合根需要了解所有注册表实现. var container = new Container(config => { config.AddRegistry<CommandHandlerRegistry>(); }); 您甚至可以选择在运行时查找所有Registry实例(您仍需要确保加载所有必需的程序集) var container = new Container(config => { var registries = ( from assembly in AppDomain.CurrentDomain.GetAssemblies() from type in assembly.DefinedTypes where typeof(Registry).IsAssignableFrom(type) where !type.IsAbstract where !type.Namespace.StartsWith("StructureMap") select Activator.CreateInstance(type)) .Cast<Registry>(); foreach (var registry in registries) { config.AddRegistry(registry); } }); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |