c# – 如何合并两个Observable,以便在任何Observable完成时结果
发布时间:2020-12-15 17:42:53 所属栏目:百科 来源:网络整理
导读:我有这个代码: var s1 = new SubjectUnit();var s2 = new SubjectUnit();var ss = s1.Merge(s2).Finally(() = Console.WriteLine("Finished!"));ss.Subscribe(_ = Console.WriteLine("Next"));s1.OnNext(new Unit());s2.OnNext(new Unit());s1.OnCompleted(
我有这个代码:
var s1 = new Subject<Unit>(); var s2 = new Subject<Unit>(); var ss = s1.Merge(s2).Finally(() => Console.WriteLine("Finished!")); ss.Subscribe(_ => Console.WriteLine("Next")); s1.OnNext(new Unit()); s2.OnNext(new Unit()); s1.OnCompleted(); // I wish ss finished here. s2.OnCompleted(); // Yet it does so here. =( 我已经使用OnError(new OperationCanceledException())解决了我的问题,但我想要一个更好的解决方案(必须有一个组合器吗?). 解决方法
或者这个,这也很整洁:
public static class Ext { public static IObservable<T> MergeWithCompleteOnEither<T>(this IObservable<T> source,IObservable<T> right) { return Observable.CreateWithDisposable<T>(obs => { var compositeDisposable = new CompositeDisposable(); var subject = new Subject<T>(); compositeDisposable.Add(subject.Subscribe(obs)); compositeDisposable.Add(source.Subscribe(subject)); compositeDisposable.Add(right.Subscribe(subject)); return compositeDisposable; }); } } 这使用了一个主题,它将确保只有一个OnCompleted被推送到CreateWithDisposable()中的观察者; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |