React Native ListView 长按删除
发布时间:2020-12-15 08:19:13 所属栏目:百科 来源:网络整理
导读:项目中React Native ListView的长按删除功能分享(基于ES5): /** * Sample React Native App * https://github.com/facebook/react-native * @flow */import React,{Component} from 'react';import { AppRegistry,StyleSheet,Text,View,ListView,TouchableO
项目中React Native ListView的长按删除功能分享(基于ES5):
/** * Sample React Native App * https://github.com/facebook/react-native * @flow */ import React,{Component} from 'react'; import { AppRegistry,StyleSheet,Text,View,ListView,TouchableOpacity } from 'react-native'; var ds = new ListView.DataSource({ rowHasChanged: (r1,r2) => { r1 !== r2 } }); var rows = ['row 1','row 2','row 3','row 4','row 5','row 6']; var XXX = React.createClass({ getInitialState() { return { dataSource: ds.cloneWithRows(rows),}; },_deleteRow(rowID) { delete rows[rowID]; this.setState({dataSource: ds.cloneWithRows(rows)}) },renderRow(rowData,sectionID,rowID) { return <TouchableOpacity onLongPress={()=>this._deleteRow(rowID)} style={{height: 60,flex: 1,borderBottomWidth: 1}}> <Text>{rowData}</Text> </TouchableOpacity> },render() { return ( <ListView dataSource={this.state.dataSource} renderRow={this.renderRow} /> ); } }); AppRegistry.registerComponent('XXX',() => XXX); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |