postgresql – 如何在psql中获取当月周日的计数?
发布时间:2020-12-13 16:08:16 所属栏目:百科 来源:网络整理
导读:如何在 postgresql中获取给定日期的星期日总数 解决方法 给定日期的星期日总数只能是0或1. 但如果您想要在给定日期范围内的星期日数量,那么您最好的选择是日历表.为了找到今年2月的星期日,我只是 select count(*) from calendarwhere cal_date between '2011
如何在
postgresql中获取给定日期的星期日总数
解决方法
给定日期的星期日总数只能是0或1.
但如果您想要在给定日期范围内的星期日数量,那么您最好的选择是日历表.为了找到今年2月的星期日,我只是 select count(*) from calendar where cal_date between '2011-02-01' and '2011-02-28' and day_of_week = 'Sun'; 要么 select count(*) from calendar where year_of_date = 2011 and month_of_year = 2 and day_of_week = 'Sun'; 这是您可以开始的基本日历表.我还包括一个PostgreSQL函数来填充日历表.我没有在8.3中测试过这个,但我很确定我没有使用8.3不支持的任何功能. 请注意,“dow”部分假设您的日期是英文.但您可以轻松编辑这些部分以匹配任何语言. (我想.但我可能错误地说“容易”.) -- Table: calendar -- DROP TABLE calendar; CREATE TABLE calendar ( cal_date date NOT NULL,year_of_date integer NOT NULL,month_of_year integer NOT NULL,day_of_month integer NOT NULL,day_of_week character(3) NOT NULL,CONSTRAINT calendar_pkey PRIMARY KEY (cal_date),CONSTRAINT calendar_check CHECK (year_of_date::double precision = date_part('year'::text,cal_date)),CONSTRAINT calendar_check1 CHECK (month_of_year::double precision = date_part('month'::text,CONSTRAINT calendar_check2 CHECK (day_of_month::double precision = date_part('day'::text,CONSTRAINT calendar_check3 CHECK (day_of_week::text = CASE WHEN date_part('dow'::text,cal_date) = 0::double precision THEN 'Sun'::text WHEN date_part('dow'::text,cal_date) = 1::double precision THEN 'Mon'::text WHEN date_part('dow'::text,cal_date) = 2::double precision THEN 'Tue'::text WHEN date_part('dow'::text,cal_date) = 3::double precision THEN 'Wed'::text WHEN date_part('dow'::text,cal_date) = 4::double precision THEN 'Thu'::text WHEN date_part('dow'::text,cal_date) = 5::double precision THEN 'Fri'::text WHEN date_part('dow'::text,cal_date) = 6::double precision THEN 'Sat'::text ELSE NULL::text END) ) WITH ( OIDS=FALSE ); ALTER TABLE calendar OWNER TO postgres; -- Index: calendar_day_of_month -- DROP INDEX calendar_day_of_month; CREATE INDEX calendar_day_of_month ON calendar USING btree (day_of_month); -- Index: calendar_day_of_week -- DROP INDEX calendar_day_of_week; CREATE INDEX calendar_day_of_week ON calendar USING btree (day_of_week); -- Index: calendar_month_of_year -- DROP INDEX calendar_month_of_year; CREATE INDEX calendar_month_of_year ON calendar USING btree (month_of_year); -- Index: calendar_year_of_date -- DROP INDEX calendar_year_of_date; CREATE INDEX calendar_year_of_date ON calendar USING btree (year_of_date); 并且填充表格的基本功能.我也没有在8.3测试过这个. -- Function: insert_range_into_calendar(date,date) -- DROP FUNCTION insert_range_into_calendar(date,date); CREATE OR REPLACE FUNCTION insert_range_into_calendar(from_date date,to_date date) RETURNS void AS $BODY$ DECLARE this_date date := from_date; BEGIN while (this_date <= to_date) LOOP INSERT INTO calendar (cal_date,year_of_date,month_of_year,day_of_month,day_of_week) VALUES (this_date,extract(year from this_date),extract(month from this_date),extract(day from this_date),case when extract(dow from this_date) = 0 then 'Sun' when extract(dow from this_date) = 1 then 'Mon' when extract(dow from this_date) = 2 then 'Tue' when extract(dow from this_date) = 3 then 'Wed' when extract(dow from this_date) = 4 then 'Thu' when extract(dow from this_date) = 5 then 'Fri' when extract(dow from this_date) = 6 then 'Sat' end); this_date = this_date + interval '1 day'; end loop; END; $BODY$ LANGUAGE plpgsql VOLATILE COST 100; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |