postgresql – 如何在psql中获取当月周日的计数?
发布时间:2020-12-13 16:08:16 所属栏目:百科 来源:网络整理
导读:如何在 postgresql中获取给定日期的星期日总数 解决方法 给定日期的星期日总数只能是0或1. 但如果您想要在给定日期范围内的星期日数量,那么您最好的选择是日历表.为了找到今年2月的星期日,我只是 select count(*) from calendarwhere cal_date between '2011
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如何在
postgresql中获取给定日期的星期日总数
解决方法
给定日期的星期日总数只能是0或1.
但如果您想要在给定日期范围内的星期日数量,那么您最好的选择是日历表.为了找到今年2月的星期日,我只是 select count(*)
from calendar
where cal_date between '2011-02-01' and '2011-02-28' and
day_of_week = 'Sun';
要么 select count(*)
from calendar
where year_of_date = 2011 and
month_of_year = 2 and
day_of_week = 'Sun';
这是您可以开始的基本日历表.我还包括一个PostgreSQL函数来填充日历表.我没有在8.3中测试过这个,但我很确定我没有使用8.3不支持的任何功能. 请注意,“dow”部分假设您的日期是英文.但您可以轻松编辑这些部分以匹配任何语言. (我想.但我可能错误地说“容易”.) -- Table: calendar
-- DROP TABLE calendar;
CREATE TABLE calendar
(
cal_date date NOT NULL,year_of_date integer NOT NULL,month_of_year integer NOT NULL,day_of_month integer NOT NULL,day_of_week character(3) NOT NULL,CONSTRAINT calendar_pkey PRIMARY KEY (cal_date),CONSTRAINT calendar_check CHECK (year_of_date::double precision = date_part('year'::text,cal_date)),CONSTRAINT calendar_check1 CHECK (month_of_year::double precision = date_part('month'::text,CONSTRAINT calendar_check2 CHECK (day_of_month::double precision = date_part('day'::text,CONSTRAINT calendar_check3 CHECK (day_of_week::text =
CASE
WHEN date_part('dow'::text,cal_date) = 0::double precision THEN 'Sun'::text
WHEN date_part('dow'::text,cal_date) = 1::double precision THEN 'Mon'::text
WHEN date_part('dow'::text,cal_date) = 2::double precision THEN 'Tue'::text
WHEN date_part('dow'::text,cal_date) = 3::double precision THEN 'Wed'::text
WHEN date_part('dow'::text,cal_date) = 4::double precision THEN 'Thu'::text
WHEN date_part('dow'::text,cal_date) = 5::double precision THEN 'Fri'::text
WHEN date_part('dow'::text,cal_date) = 6::double precision THEN 'Sat'::text
ELSE NULL::text
END)
)
WITH (
OIDS=FALSE
);
ALTER TABLE calendar OWNER TO postgres;
-- Index: calendar_day_of_month
-- DROP INDEX calendar_day_of_month;
CREATE INDEX calendar_day_of_month
ON calendar
USING btree
(day_of_month);
-- Index: calendar_day_of_week
-- DROP INDEX calendar_day_of_week;
CREATE INDEX calendar_day_of_week
ON calendar
USING btree
(day_of_week);
-- Index: calendar_month_of_year
-- DROP INDEX calendar_month_of_year;
CREATE INDEX calendar_month_of_year
ON calendar
USING btree
(month_of_year);
-- Index: calendar_year_of_date
-- DROP INDEX calendar_year_of_date;
CREATE INDEX calendar_year_of_date
ON calendar
USING btree
(year_of_date);
并且填充表格的基本功能.我也没有在8.3测试过这个. -- Function: insert_range_into_calendar(date,date)
-- DROP FUNCTION insert_range_into_calendar(date,date);
CREATE OR REPLACE FUNCTION insert_range_into_calendar(from_date date,to_date date)
RETURNS void AS
$BODY$
DECLARE
this_date date := from_date;
BEGIN
while (this_date <= to_date) LOOP
INSERT INTO calendar (cal_date,year_of_date,month_of_year,day_of_month,day_of_week)
VALUES (this_date,extract(year from this_date),extract(month from this_date),extract(day from this_date),case when extract(dow from this_date) = 0 then 'Sun'
when extract(dow from this_date) = 1 then 'Mon'
when extract(dow from this_date) = 2 then 'Tue'
when extract(dow from this_date) = 3 then 'Wed'
when extract(dow from this_date) = 4 then 'Thu'
when extract(dow from this_date) = 5 then 'Fri'
when extract(dow from this_date) = 6 then 'Sat'
end);
this_date = this_date + interval '1 day';
end loop;
END;
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
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