使用POST将文件从iOS发送到PHP

发布时间：2020-12-15 01:46:05 所属栏目：百科来源：网络整理

导读：我正在尝试将音频文件发送到PHP服务器.这是Objective-C代码： NSData *data = [NSData dataWithContentsOfFile:filePath];NSLog(@"File Size: %i",[data length]);//set up requestNSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];[reque

我正在尝试将音频文件发送到PHP服务器.这是Objective-C代码：

NSData *data = [NSData dataWithContentsOfFile:filePath];

NSLog(@"File Size: %i",[data length]);

//set up request
NSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

//required xtra info
NSString *boundary = @"---------------------------14737809831466499882746641449";
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"];

//body of the post
NSMutableData *postbody = [NSMutableData data];
[postbody appendData:[[NSString stringWithFormat:@"rn--%@--rn",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name="thefile"; filename="recording"rn"] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:[[NSString stringWithString:@"Content-Type: application/octet-streamrn"] dataUsingEncoding:NSUTF8StringEncoding]];
[postbody appendData:data];
[postbody appendData:[[NSString stringWithFormat:@"rn--%@--rn",boundary] dataUsingEncoding:NSUTF8StringEncoding]];

[request setHTTPBody:postbody];
apiConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];

这是PHP代码：

if (is_uploaded_file($_FILES['thefile']['tmp_name'])) {
    echo "FILE NAME: ".$_FILES['thefile']['name'];
} else {
    echo "Nothing";
}

文件大小取决于录制的音频长度,但有数据.

我得到了“没什么”的回应.

解决方法

要调试：在PHP端,尝试：

$file = $_POST['name'];
echo $file

尝试使用以下代码段代替当前代码.将URL(www.yourWebAddress.com)和脚本名称更改为适合您问题的值.

NSData *data = [NSData dataWithContentsOfFile:filePath];
NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];
[urlString appendFormat:@"%@",data];
NSData *postData = [urlString dataUsingEncoding:NSASCIIStringEncoding 
                                   allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
NSString *baseurl = @"https://www.yourWebAddress.com/yourServerScript.php"; 

NSURL *url = [NSURL URLWithString:baseurl];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:url];
[urlRequest setHTTPMethod: @"POST"];
[urlRequest setValue:postLength forHTTPHeaderField:@"Content-Length"];
[urlRequest setValue:@"application/x-www-form-urlencoded" 
          forHTTPHeaderField:@"Content-Type"];
[urlRequest setHTTPBody:postData];

NSURLConnection *connection = [NSURLConnection connectionWithRequest:urlRequest delegate:self];
[connection start];

NSLog(@"Started!");

在服务器端,我有以下代码：

<?php

    $name  = $_POST['name'];
    $filename  = $_POST['filename'];
    echo "Name = '" . $name . "',filename = '" . $filename . "'.";

    error_log ( "Name = '" . $name . "',filename = '" . $filename . "'." );

?>

我收到了以下输出：

[23-May-2012 11:56:18] Name =’thefile’,filename =’recording’.

我不知道为什么它不适合你.你必须缺少一步.尝试在上面引用“数据”的url POST代码中注释掉两行,以确保您至少可以获得服务器端的名称和文件名的纯文本.

祝你好运！

（编辑：李大同）

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